Question

我目前正在尝试添加自定义工具提示作为我的Visual Studio的扩展程序。

然而，当悬停在关键字上方时，（因为我有很长的描述，我尝试使用\ r \ n但它显然不起作用，并且在工具提示中显示为\ r \ n所以我使用了）

//var reader = new StreamReader(File.OpenRead(@"C:\xx\QuickInfo.csv"));
/*while (!reader.EndOfStream)
    {
        var line = reader.ReadLine();
        var values = line.Split(',');
        //add in values in position 0 and 1 
        m_dictionary.Add(values[0], values[1].Replace("<br>", Environment.NewLine));
    }*/

空间

internal class VCLToolTipSource: IQuickInfoSource
{
    private VCLToolTipSourceProvider m_provider;
    private ITextBuffer m_subjectBuffer;
    private Dictionary<string, string> m_dictionary;
    public VCLToolTipSource(VCLToolTipSourceProvider provider, ITextBuffer subjectBuffer)
    {
        m_provider = provider;
        m_subjectBuffer = subjectBuffer;

        m_dictionary = new Dictionary<string, string>();

        //CSV for Quick Info
        //var reader = new StreamReader(File.OpenRead(@"C:\xx\QuickInfo.csv"));
        //For going through CSV positions 0,1//
        /*while (!reader.EndOfStream)
        {
            var line = reader.ReadLine();
            var values = line.Split(',');
            //add in values in position 0 and 1 
            m_dictionary.Add(values[0], values[1].Replace("<br>", Environment.NewLine));
        }*/

        //List of all tool tips//


        m_dictionary.Add("keyword", "value");
        m_dictionary.Add("adapt", " - Process given file  <br>Syntax: #adapt[(-samelevel|-continue|-samelevel-continue|-copy)][:] path [output-folder] [output-file]( vcl-command )*[#endadapt]<br>Variations:<br><br> -samelevel :  The scope of the adapted file will be raised to the current level which makes it possible to override variables<br> -continue  :  If the adaptable file is not found continue processing. (warning message instead of stop processing with error)<br>Note: #adapt-continue will open the file and process it. Unlike #adapt-copy.<br> -copy :  Instead of processing the file");

替换所有＆＃34;＆lt; br ＆gt;＆＃34;与Environment.Newline缩短它。

但是，现在我不想使用CSV文件导入数据，如何从字典中读取数据并替换＆lt; br ＆gt;用换行符？

谢谢

Answer 1

也许这更符合你想做的事情？

m_dictionary = m_dictionary.ToDictionary(
                                k => k.Key, 
                                v => v.Value.Replace("<br>", Environment.NewLine));

这将遍历整个字典，并将所有"<br>"值替换为Environment.NewLine。

Answer 2

您是否尝试在字符串末尾添加yourstring.Replace（“<br>”，Environment.NewLine）。

m_dictionary
    .Add("adapt", 
         " - Process given file  <br>Syntax: #adapt[(-samelevel|-continue|-samelevel-continue|-copy)][:] path [output-folder] [output-file]( vcl-command )*[#endadapt]<br>Variations:<br><br> -samelevel :  The scope of the adapted file will be raised to the current level which makes it possible to override variables<br> -continue  :  If the adaptable file is not found continue processing. (warning message instead of stop processing with error)<br>Note: #adapt-continue will open the file and process it. Unlike #adapt-copy.<br> -copy :  Instead of processing the file"
    .Replace("<br>", Environment.NewLine));

Answer 3

将“<br>"替换为Environment.NewLine或\n。

代码：

string str =  " - Process given file  <br>Syntax: #adapt[(-samelevel|-continue|-samelevel-continue|-copy)][:] path [output-folder] [output-file]( vcl-command )*[#endadapt]<br>Variations:<br><br> -samelevel :  The scope of the adapted file will be raised to the current level which makes it possible to override variables<br> -continue  :  If the adaptable file is not found continue processing. (warning message instead of stop processing with error)<br>Note: #adapt-continue will open the file and process it. Unlike #adapt-copy.<br> -copy :  Instead of processing the file";
   str =  str.Replace("<br>", Environment.NewLine);

或

str =  str.Replace("<br>", "\n");

输出： - 处理给定文件
语法：#adapt [（ - samelevel | -continue | -samelevel-continue | -copy）] [：] path [output-folder] output-file * [#endadapt] 变化：

-samelevel：已调整文件的范围将提升到当前级别，从而可以覆盖变量 -continue：如果找不到自适应文件，则继续处理。（警告消息而不是因错误而停止处理）注意：#adcust-continue将打开文件并进行处理。与#adcust-copy不同。 -copy：而不是处理文件

虽然我的上述答案在理想情况下运行良好，但你必须涵盖所有情况。

public string ReplaceBRwithNewline(string txtVal)  
{  
    string newText = "";  
    // Create Regex    
    System.Text.RegularExpressions.Regex regex =   
        new System.Text.RegularExpressions.Regex(@"(<br />|<br/>|</ br>|</br>)");  
    // Replace new line with <br/> tag    
    newText = regex.Replace(txtVal, "\r\n");  
    // Result    
    return newText;  
}

我在这里用\r\n替换，因为在某些浏览器上它与\n一起使用，而在某些浏览器上它与\r\n一起使用。

用NewLine替换字典值

3 个答案: