Question

我在我的网络应用程序中使用spring安全核心进行身份验证，但我无法弄清楚如何从我的User类中获取自定义信息这是我的用户类：

package core

import beans.Colaborador
import groovy.transform.EqualsAndHashCode
import groovy.transform.ToString

@EqualsAndHashCode(includes = 'username')
@ToString(includes = 'username', includeNames = true, includePackage = false)
class Usuario implements Serializable {

    private static final long serialVersionUID = 1

    transient springSecurityService
    String username
    String password
    boolean enabled = true
    boolean accountExpired
    boolean accountLocked
    boolean passwordExpired
    Colaborador colaborador

    Usuario(String username, String password) {
        this()
        this.username = username
        this.password = password
    }

    Set<Permissao> getAuthorities() {
        UsuarioPermissao.findAllByUsuario(this)*.permissao
    }

    def beforeInsert() {
        encodePassword()
    }

    def beforeUpdate() {
        if (isDirty('password')) {
            encodePassword()
        }
    }

    protected void encodePassword() {
        password = springSecurityService?.passwordEncoder ? springSecurityService.encodePassword(password) : password
    }

    static transients = ['springSecurityService']

    static constraints = {
        username blank: false, unique: true
        password blank: false
        colaborador nullable: true
    }

    static mapping = {
        password column: '`password`'
    }
}

我想要使用的信息是在Colaborador对象中，但是如果我尝试使用 sec：loggedInUserInfo 来访问它并且没有成功，我读过我需要创建一个Custom UserDetailsService ，但我无法找到创建它的方式和位置，有人能帮我一把吗？

谢谢！

@Edit

我尝试按照文档编写并创建了两个类

import beans.Colaborador
import grails.plugin.springsecurity.userdetails.GrailsUser
import org.springframework.security.core.GrantedAuthority

class MyUserDetails extends GrailsUser {

    final Colaborador colaborador

    MyUserDetails(String username, String password, boolean enabled,
                  boolean accountNonExpired, boolean credentialsNonExpired,
                  boolean accountNonLocked,
                  Collection<GrantedAuthority> authorities,
                  long id, Colaborador colaborador) {
        super(username, password, enabled, accountNonExpired,
                credentialsNonExpired, accountNonLocked, authorities, id)
        this.colaborador = colaborador
    }
}

和

package core    
import grails.plugin.springsecurity.SpringSecurityUtils
import grails.plugin.springsecurity.userdetails.GrailsUserDetailsService
import grails.plugin.springsecurity.userdetails.NoStackUsernameNotFoundException
import grails.transaction.Transactional
import org.springframework.security.core.authority.SimpleGrantedAuthority
import org.springframework.security.core.userdetails.UserDetails
import org.springframework.security.core.userdetails.UsernameNotFoundException

class MyUserDetailsService implements GrailsUserDetailsService {
    static final List NO_ROLES = [new SimpleGrantedAuthority(SpringSecurityUtils.NO_ROLE)]

    UserDetails loadUserByUsername(String username, boolean loadRoles)
            throws UsernameNotFoundException {
        return loadUserByUsername(username)
    }

    @Transactional(readOnly = true, noRollbackFor = [IllegalArgumentException, UsernameNotFoundException])
    UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {

        Usuario user = Usuario.findByUsername(username)
        if (!user) throw new NoStackUsernameNotFoundException()
        def roles = user.authorities
        def authorities = roles.collect {
            new SimpleGrantedAuthority(it.authority)
        }

        return new MyUserDetails(user.username, user.password, user.enabled,
                !user.accountExpired, !user.passwordExpired,
                !user.accountLocked, authorities ?: NO_ROLES, user.id,
                user.colaborador)
    }
}

当我在我的应用程序中登录时，我收到此错误：

2016-11-14 11:56:46,061 [http-bio-80-exec-4] ERROR authentication.GrailsUsernamePasswordAuthenticationFilter  - An internal error occurred while trying to authenticate the user.
Message: Could not find matching constructor for: java.lang.Object(java.lang.String, java.lang.String, java.lang.Boolean, java.lang.Boolean, java.lang.Boolean, java.lang.Boolean, java.util.ArrayList, java.lang.Long)

Answer 1

documentation概述（一步一步）如何创建自定义// extracted from above code in the while loop // stringstream ss(type[count]); getline(ss, item1, ';'); cout<<item1<<endl; //another whileloop inside a whileloop to save item1 into an another array?。它将引导您完成创建它并在您的应用程序中注册它的过程。

Grails Spring安全核心 - 自定义用户信息？

1 个答案: