Question

我正在编写一个函数，我会通过字典。字典包含艺术家作为键，他们的绘画作为价值。我需要在具有最大区域的字典中找到该绘画，如果有两个具有相同区域的绘制，则应将它们作为元组列表返回。

示例词典：

{
        'A, Jr.':[("One",1400,10,20.5,"oil paint","Austria"),("Three",1400,100.0,100.0,"oil paint","France"),("Twenty",1410,50.0,200.0,"oil paint","France")],
        'X':[("Eight",1460, 100.0, 20.0, "oil paint","France"),("Six",1465,10.0, 23.0, "oil paint", "France"),("Ten",1465,12.0,15.0,"oil paint","Austria"),("Thirty",1466,30.0,30.0,"watercolor","Germany")],   
        'M':[("One, Two", 1500, 10.0, 10.0, "panel","Germany")]
        }

基本上，四位数字是绘画或艺术品创作的年份，接下来的两个数字是长度和宽度。我需要在乘以长度和宽度时返回具有最大面积的值。所以对于上面的字典，函数find_largest应该返回

find_largest(dictionary2())

[('A, Jr.', 'Three'), ('A, Jr.', 'Twenty')]

因为＆＃34;三＆＃34; 100 * 100 = 10,000 ＆＃34; Twenty＆＃34;和＃34; Twenty＆＃34; 50 * 200 = 10,000绘画它们都作为元组返回列表中。

有人有关于如何做到这一点的建议吗？我已经开始使用以下代码，但我认为这不是正确的方法。

def find_largest(dictionary):
    matches = {}
    for key, the_list in db.items():
        for record in the_list:
            value = record[4]
            if dictionary in record:
                if key in matches:
                    max(the_list)
                    max(lst, key=lambda tupl: tupl[2]*tupl[3])
                    matches[key].append(record)
                else:
                    matches[key] = [record]
    return matches

这基本上是来自早期函数的代码，只有一些重大更改。这个基本框架适用于我的一些目标。我添加了max（匹配），但我意识到除非函数乘以长度和宽度然后查找最大值，否则不会做太多。如果有人有建议会有帮助

Answer 1

可能更容易跟踪当前的最大值

data = {
        'A, Jr.':[("One",1400,10,20.5,"oil paint","Austria"),("Three",1400,100.0,100.0,"oil paint","France"),("Twenty",1410,50.0,200.0,"oil paint","France")],
        'X':[("Eight",1460, 100.0, 20.0, "oil paint","France"),("Six",1465,10.0, 23.0, "oil paint", "France"),("Ten",1465,12.0,15.0,"oil paint","Austria"),("Thirty",1466,30.0,30.0,"watercolor","Germany")],   
        'M':[("One, Two", 1500, 10.0, 10.0, "panel","Germany")]
        }

def find_largest(d):
    matches = []
    max_value = 0
    for key in d:
        for record in d[key]:
            value = record[2] * record[3]
            if value > max_value:
                matches = [(key, record[0])]
                max_value = value
            elif value == max_value:
                matches.append((key, record[0]))
    return matches

# Output
>>> find_largest(data)
[('A, Jr.', 'Three'), ('A, Jr.', 'Twenty')]

寻找字典中最大的区域

1 个答案: