我想弄清楚当从下拉菜单中选择其他的值时,如何显示html 输入字段。现在,下拉列表的值来自MySQL数据库查询的结果,这可以工作,但我似乎无法弄清楚当我选择其他选项时如何获得输入。
$query = mysql_query("SELECT type FROM Dropdown_Service_Type"); // Run your query
echo '<select name="service_type">'; // Open your drop down box
echo '<option value="NULL"></option>';
// Loop through the query results, outputing the options one by one
while ($row = mysql_fetch_array($query)) {
echo '<option value="'.$row['type'].'">'.$row['type'].'</option>';
}
echo '<option value="Other">Other</option>';
echo '</select>';// Close your drop down box
答案 0 :(得分:3)
使用javascript,如下例所示。我们可以使用样式属性添加input字段并默认隐藏它:
<input name='otherInput' id='otherInput' type="text" style="display: none" />
var otherInput;
function checkOptions(select) {
otherInput = document.getElementById('otherInput');
if (select.options[select.selectedIndex].value == "Other") {
otherInput.style.display = 'block';
}
else {
otherInput.style.display = 'none';
}
}
&#13;
<select onchange="checkOptions(this)" name="service_type" id="service_type">
<option value="NULL"></option>
<option value="43">43</option>
<!-- other options from your database query results displayed here -->
<option value="Other">Other</option>
</select>
<!-- the style attribute here has display none initially, so it will be hidden by default -->
<input name='otherInput' id='otherInput' type="text" style="display: none" />
&#13;
有第三方库,如jQuery,AngularJS,PrototypeJS等,可以通过添加DOM操作的快捷方法来使代码更简单(尽管你应该阅读this post)。例如,使用jQuery,使用.on()(用于事件处理程序绑定),.show()和.hide()用于输入显示切换等:
var otherInput;
var serviceTypeInput = $('#service_type');
serviceTypeInput.on('change', function() {
otherInput = $('#otherInput');
if (serviceTypeInput.val() == "Other") {
otherInput.show();
} else {
otherInput.hide();
}
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select name="service_type" id="service_type">
<option value="NULL"></option>
<option value="43">43</option>
<option value="Other">Other</option>
</select>
<input name='otherInput' id='otherInput' type="text" style="display: none" />
&#13;
答案 1 :(得分:0)
$(function() {
$('#sample').change(function() {
var val = this.value; // get the value of the select.
if (val == 'other') { // if the value is equal to "other" then append input below the select
$('html').append('<input type="text" id="inputOther"/>');
} else { // else then remove the input
$('#inputOther').remove();
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="sample">
<option value="test1">test1</option>
<option value="test2">test2</option>
<option value="test3">test3</option>
<option value="other">other</option>
</select>