Question

类似于这些问题：

在这样的文件中：

define('_DB_NAME_', 'anything');
define('_DB_USER_', 'something else');
define('_DB_PASSWD_', 'and another value');

如何通过引用键值anything，something来使用sed替换值another，_DB_NAME_和_DB_USER_（未知）和_DB_PASSWD？

Answer 1

你可能想要：

sed -E "
  s/('_DB_NAME_', ')[^']+/\1ABC/
  s/('_DB_USER_', ')[^']+/\1DEF/
  s/('_DB_PASSWD_', ')[^']+/\1GHI/
"

我认为awk更具可读性：

awk -F "'" -v OFS="'" '
    $2 == "_DB_NAME_"   {$4 = "ABC"}
    $2 == "_DB_USER_"   {$4 = "DEF"}
    $2 == "_DB_PASSWD_" {$4 = "GHI"}
    {print}
'

Answer 2

sed "s/\(define('_DB_NAME_', \).*/\1'new value');/" filename

同样适用于其他两个。

如果要更改文件，可以使用-i，但必须小心，不同版本的sed处理方式不同。

Answer 3

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其中tempfile包含您拥有的代码。输出看起来像这样

sed -i -e 's/anything/newanything/g;s/something/newthing/g;s/another/newanother/' tempfile

使用带有sed的bash脚本修改文件

3 个答案: