Question

我想当我在EditText中写5然后我点击按钮我希望TextView更改为5，然后如果我写6并再次单击按钮我希望TextView更改为11 ...

<EditText
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:hint="how much do you want to add ?"
    android:id="@+id/editText" />

<TextView
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:text="0"
    android:textSize="50sp"
    android:layout_centerHorizontal="true"
    android:layout_alignParentTop="true"
    android:layout_alignParentStart="true"
    android:layout_marginTop="86dp"
    android:id="@+id/TextView" />

<Button
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:id="@+id/add"
    android:onClick="add"
    android:layout_below="@id/editText"
    android:hint="add"/>

Answer 1

您可以查看以下代码段。确保添加条件/检查输入始终为数字：

yourbtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            if(yourtxtview.getText().toString().trim().length()>0 ){
                if(youredtText.getText().toString().trim().length()>0){
                    yourtxtview.setText(String.valueOf(Integer.valueOf(yourtxtview.getText().toString())
                            +Integer.valueOf(youredtText.getText().toString())));
                }else{
                    yourtxtview.setText(String.valueOf(Integer.valueOf(yourtxtview.getText().toString())+
                            0));

                }
            }else if(youredtText.getText().toString().trim().length()>0){
                yourtxtview.setText(String.valueOf(Integer.valueOf(youredtText.getText().toString())+
                        0));
            }
        }
    });

Answer 2

class SearchPresenter<T>(val network: Network) : BasePresenter<SearchView<T>>()

从EditText获取数字到TextView并添加

2 个答案: