Question

伙计我的应用程序使用相机拍照我使用以下代码拍照

public void takepic(View view) {

        TextView schtitle = (TextView) findViewById(R.id.Sitename);
        String schname = schtitle.getText().toString();
            String[] tokens = schname.split(" ");
            String timeStamp = new SimpleDateFormat("dd-MM-yyyy-HH-mm-ss").format(new Date());
            String imageFileName = tokens[0] + "-" + timeStamp + ".jpg";
            TextView myAwesomeTextView = (TextView)findViewById(R.id.filetext);

          //in your OnCreate() method
          myAwesomeTextView.setText(imageFileName);
            Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);    


                File path = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES);
                String name = imageFileName;
                File file = new File(path, name );
                outputFileUri = Uri.fromFile(file);
                intent.putExtra(MediaStore.EXTRA_OUTPUT, outputFileUri);
                startActivityForResult(intent, TAKE_PICTURE); 


       }

除了Nougat之外，其他所有方法都可以正常使用

我理解他们在棉花糖中所做的，你现在需要权限，不能再使用文件URI了

我找不到任何关于如何在牛轧糖中拍照的示例代码，有人可以指出我正确的方向，如何修改我的代码以允许这种情况发生？

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标记

Answer 1

问题是文件：// uri不再被授权。

而不是这个，你必须使用FileProvider。

看看这里：https://inthecheesefactory.com/blog/how-to-share-access-to-file-with-fileprovider-on-android-nougat/en

Answer 2

在此引用此内容作为参考。

我们现在有一个更新的文档，介绍如何使用文件uri将摄像头意图存储在android的训练部分下。

https://developer.android.com/training/camera/photobasics.html

Answer 3

 public void openShare(View view) {
        // save bitmap to cache directory
        try {
            bitmap = ((BitmapDrawable) iv.getDrawable()).getBitmap();

            File cachePath = new File(getCacheDir(), "images");

            if (!cachePath.exists())
                cachePath.mkdirs();

            FileOutputStream stream = new FileOutputStream(cachePath + "/" + imageName);
            bitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
            stream.close();

            shareImage();

        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    private void shareImage() {
        File imagePath = new File(getCacheDir(), "images");
        File newFile = new File(imagePath, imageName);
        Uri contentUri = MyFileProvider.getUriForFile(this, "com.example.kushaalsingla.contentsharingdemo", newFile);

        if (contentUri != null) {
            Intent shareIntent = new Intent();
            shareIntent.setAction(Intent.ACTION_SEND);
            shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION); // temp permission for receiving app to read this file
            shareIntent.setDataAndType(contentUri, getContentResolver().getType(contentUri));
            shareIntent.putExtra(Intent.EXTRA_STREAM, contentUri);
            startActivity(Intent.createChooser(shareIntent, "Choose an app"));
        }
    }

##################加入清单

       <provider
            android:name=".MyFileProvider"
            android:authorities="com.example.kushaalsingla.contentsharingdemo"
            android:grantUriPermissions="true"
            android:exported="false">
            <meta-data
                android:name="android.support.FILE_PROVIDER_PATHS"
                android:resource="@xml/filepaths" />
        </provider>

################## filepaths.xml ########################

<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
    <cache-path name="shared_images" path="images/"/>
</paths>

Android N FileUriExposedException

3 个答案: