我使用的Laravel 5.3广告在通过hasMany关系进行保存方面存在问题。
我有桌面工作和工地,有一对多关系,即每个工地有一个或多个工作
但是当我尝试使用job_job_site_id
在作业表中添加associate()
时,它会向我发送错误消息:
SQLSTATE[42703]: Undefined column: 7 ERROR: column "job_site" of relation "job" does not exist
LINE 1: update "job" set "updated_at" = $1, "job_site" = $2 ...
^ (SQL: update "job" set "updated_at" = 2016-11-13 15:29:37, "job_site" = where "job_id" = 3)
SQLSTATE[42703]: Undefined column: 7 ERROR: column "job_site" of relation "job" does not exist
LINE 1: update "job" set "updated_at" = $1, "job_site" = $2 ...
^
数据库结构:
job (1st table)
– job_id
– job_name
– job_job_site_id
- created_at
- updated_at
job_site (2nd table)
– job_site_id
– job_site_name
- created_at
- updated_at
模特职业:
class Job extends Model
{
protected $table = 'job';
protected $primaryKey = 'job_id';
public function jobsite() {
return $this->belongsTo('App\Models\JobSite', 'job_site', 'job_job_site_id', 'job_site_id');
}
}
模型类JobSite:
class JobSite extends Model
{
protected $table = 'job_site';
protected $primaryKey = 'job_site_id';
public function jobs() {
return $this->hasMany('App\Models\Job', 'job', 'job_job_site_id', 'job_id');
}
}
控制器:
public function jobsiteJobs($data)
{
$jobsite = JobSite::find(3);
$job_id = array(1,2,3);
if (!empty($jobsite)) {
foreach ($job_id as $id) {
$job = Job::find($id);
$job->jobsite()->associate($jobsite);
$job->save();
}
return 'Added';
}
else {
return 'Not found';
}
}
我的关系定义不正确吗?
答案 0 :(得分:1)
是的,您已经错误地定义了关系。正确的版本如下:
模特职业:
class Job extends Model
{
protected $table = 'job';
protected $primaryKey = 'job_id';
public function jobsite() {
return $this->belongsTo('App\Models\JobSite', 'job_job_site_id', 'job_site_id');
}
}
Model Class JobSite:
class JobSite extends Model
{
protected $table = 'job_site';
protected $primaryKey = 'job_site_id';
public function jobs() {
return $this->hasMany('App\Models\Job', 'job_job_site_id', 'job_site_id');
}
}