Question

在Odoo 8中，我能够使用XML定义服务器操作，例如：

ERROR:odoo.http:Exception during JSON request handling.
Traceback (most recent call last):
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 638, in _handle_exception
    return super(JsonRequest, self)._handle_exception(exception)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 675, in dispatch
    result = self._call_function(**self.params)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 331, in _call_function
    return checked_call(self.db, *args, **kwargs)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/service/model.py", line 119, in wrapper
    return f(dbname, *args, **kwargs)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 324, in checked_call
    result = self.endpoint(*a, **kw)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 933, in __call__
    return self.method(*args, **kw)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 504, in response_wrap
    response = f(*args, **kw)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/addons/web/controllers/main.py", line 1129, in run
    result = request.env['ir.actions.server'].browse([action_id]).run()
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/addons/base/ir/ir_actions.py", line 964, in run
    res = func(action, eval_context=eval_context)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/addons/base/ir/ir_actions.py", line 793, in run_action_code_multi
    safe_eval(action.code.strip(), eval_context, mode="exec", nocopy=True)  # nocopy allows to return 'action'
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/tools/safe_eval.py", line 301, in safe_eval
    return unsafe_eval(c, globals_dict, locals_dict)
File "", line 1, in <module>
ValueError: <type 'exceptions.NameError'>: "name 'self' is not defined" while evaluating
u'self.action(cr, uid, context=context)'

这会执行我的module.model.action（）方法。

在Odoo 10中，此代码抛出异常：

{{1}}

我在Odoo文档中没有看到有关https://www.odoo.com/documentation/10.0/reference/actions.html#code的服务器操作的任何有趣内容

文档明确声明self是服务器操作的评估上下文的一部分，请参阅https://www.odoo.com/documentation/10.0/reference/actions.html#reference-actions-server-context

如何在Odoo 10中创建服务器操作？

Answer 1

在Odoo 10中声明服务器操作时，不需要 self 对象。我们可以使用 env ['model.name'] 直接访问模型/对象

尝试使用以下代码：

<?xml version="1.0" encoding="utf-8" ?>
<odoo>
  <data>
    <record id="action" model="ir.actions.server">
      <field name="name">My Action</field>
      <field name="model_id" ref="model_module_model"/>
      <field name="code">
        if context.get('active_model') == 'your.module.model' and context.get('active_ids'):
                action = env['module.model'].browse(context['active_ids']).action()
    </record>
  </data>
</odoo>

修改

我们可以使用这些 env ['module.model']。action（）在没有 active_ids 时执行方法

Answer 2

campaign_id   post_id
-----------   -------- 
100           1
100           1
100           1

Answer 3

自从Odoo 10以来，旧的API被完全删除了。所以我想你的旧样式调用cr，uid和context是问题所在。尝试只调用模型，或者如果有想要调用方法的记录，请使用它。

# model call
model.action()
# record call
object.action()

一点提示：尝试在客户端的设置下创建服务器操作。键入“代码”是默认值，您将获得有关此功能的一些文档:-)

如何在Odoo 10中创建服务器操作？

3 个答案: