Question

我收到以下错误，使用快递在Node.js中执行应用程序。我正在使用Mongoose进行数据库操作，我已经详细介绍了我的设计

Party.js

var mongoose = require("mongoose");

var partySchema = new mongoose.Schema({
    partyName: String,
    songs: [
         {
                 type: mongoose.Schema.Types.ObjectId,
                ref: "Song"
         }
   ]
});

module.exports = mongoose.model("Party", partySchema);

Song.js

var mongoose = require("mongoose");

var songsSchema = new mongoose.Schema({
    videoId: String,
    videoName: String
});

module.exports = mongoose.model("Song", songsSchema);

我的App.js

app.post("/search/addSong", function(req, res) {
    Party.find({partyName:"hello"},function(err,party){
        if(err){
            console.log("Failed in find");
        } else {
            console.log(party);
            // console.log(typeof(req.body.videoId));
            var videoId = req.body.videoId;

            var newSong = [ {
                videoId:req.body.videoId,
                videoName:req.body.videoName
            }
            ];
            Song.create(newSong, function(err, createdSong){
       if(err){
           console.log("Error creating a new party");
       } else  {
           console.log(createdSong);
           party.songs.push(createdSong);// ERROR ON THIS LINE
           party.save();
           res.redirect("/search");
       }
    });
        }
    });
    res.render("addSong");
});

我可以单独创建Party和Song的集合对象，当我将歌曲添加到派对队列时，我收到以下错误：

TypeError: Cannot read property 'push' of undefined

任何人都可以让我知道我在这里失踪了什么.. !!

提前致谢。!!

Answer 1

find返回一个在数组中转换的游标。如果您期望单个文档，请调用findOne。

app.post("/search/addSong", function(req, res) {
    Party.findOne({partyName:"hello"},function(err,party){
        if(err){
            console.log("Failed in find");
        } else {
            console.log(party);
            // console.log(typeof(req.body.videoId));
            var videoId = req.body.videoId;

            var newSong = [ {
                videoId:req.body.videoId,
                videoName:req.body.videoName
            }
            ];
            Song.create(newSong, function(err, createdSong){
       if(err){
           console.log("Error creating a new party");
       } else  {
           console.log(createdSong);
           party.songs.push(createdSong);// ERROR ON THIS LINE
           party.save(function(err){
             res.redirect("/search");
           });
       }
    });
        }
    });
    res.render("addSong");
});

还将重定向放在save的回调中，它将确保仅在保存完成时调用重定向，否则它将重定向而不保存，从而提供javascript的异步性质。

TypeError：无法读取未定义的Mongoose属性'push'

1 个答案: