删除两列匹配的位置

Question

我有两张桌子

Person (contain oldest date (farthest in future) when person moved OR WILL moved to another address)

ID                OLDESTADDRESSMOVEDATE

1                     20161117
2                     20171211
3                     20160101


Address           

PersonID             AddressMOVETODATE
 1                       20161117
 1                       20161111
 1                       20141018
 2                       20171211
 2                       20151210

现在我想编写一个DELETE查询，它将为PERSON中的每个人删除地址，其中AddressMOVETODATE比OLDESTADDRESSMOVEDATE colum中的那个更早

e.g。

如果我运行该查询，则ADDRESS表中的其余行应为

PersonID             AddressMOVETODATE
1                       20161117
2                       20171211

我试过了

DELETE FROM ADDRESS WHERE PERSONID = PERSON.ID and AddressMOVETODATE < Person.OLDESTADDRESSMOVEDATE

但它不起作用。另外，我们如何确保只输入Person表的CORRESPONDING列，例如我们不想通过放置

来搞砸

Person ID = 1 and Person.OLDESTADDRESSMOVEDATE = 20171211 (of Person 2)

请帮忙。

谢谢，

艾登

Answer 1

您可以使用row_number，cte和delete

进行查询

;WITH cte AS
(
    SELECT *, RowN = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY AddressMoveDate DESC) FROM Address
)
DELETE FROM cte WHERE RowN > 1