Javascript / Jquery专家,
我有这个脚本。
的JavaScript
$(document).ready(function(){
var number = 1;
var timer = setInterval(function() {
if(number == 1){str = "Professionl Designer"}
else if(number == 2){str = "Professionl Marketer"}
else if(number == 3){str = "Professionl Programmer"}
else if(number == 4){str = "Professionl Developer"}
$("#test").html("<div>"+ str+"</div>").fadeTo(600, 0.1).fadeTo(600, 1.0);
++number;
if(number == 5){
clearInterval(timer);
}
}, 2500);
});
HTML
<div id = "test"></div>
检查其fiddle
此脚本在显示最后一个标题后停止。
在连续循环中显示最后一个标题后,它应该再次显示第一个标题。
答案 0 :(得分:0)
每次循环后重置数字
$(document).ready(function() {
var pro = ["Professional Designer",
"Professional Marketer",
"Professional Programmer",
"Professional Developer"];
var number = 0;
var timer = setInterval(function() {
$("#test").html("<div>" + pro[number] + "</div>").fadeTo(600, 0.1).fadeTo(600, 1.0);
++number;
if (number == 4) {
number = 0;
}
}, 2500);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="test">
</div>
或更短,使用mod %
$(document).ready(function() {
var pro = ["Professional Designer",
"Professional Marketer",
"Professional Programmer",
"Professional Developer"];
var number = 0;
var timer = setInterval(function() {
$("#test").html("<div>" + pro[number] + "</div>").fadeTo(600, 0.1).fadeTo(600, 1.0);
number = (number+1) %4;
}, 2500);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="test">
</div>