Question

我有STATUS专栏。值被批准，待定，拒绝。我必须计算机票在PENDING中的天数。

ID      Status       Date
BNM       Pend        11/nov/16
BNM       Pend        12/nov/16
ABC       Pend        11/nov/16
BNM       Pend        12/nov/16
ABC       Pend        11/nov/16
ABC       Pend       12/nov/16
CVD       pend        11/nov/16
CVD       pend        12/nov/16
BNM       Pend        10/NOV/16
ABC       Pend         10/NOV/16
CVD       Pend         10/NOV/16
CVD       Approv        09/NOV/16
CVD       PEND           08/NOV/16

当我在13 / nov / 16上运行查询时。

BNM-3 days
ABC-3 days
"CVD-5days" (counted as 5 days but it should count as 3 days).

从08年11月开始计算，但它应该从10月16日开始计算。有关状态的最新消息将于09年11月9日开始。

Select t.ID,(t.date),t2.nofdays,t1.status
     from table1 t
     inner join 
         (  select tt.id,max(tt.days) 
                  from table1 tt
               group by ...)t2
                  on t.id=t2.id
 inner join 
        (  (  select ttt.id,max(ttt.days), count(ttt.days) as noofdays

                  from table1 ttt 
                where status like 'PEND%'
               group by ...)t2

            on t1.id=t2.id and t1.date=t2.date

where trunc(t.date)=trunc(sysdate-1)
group by .....)

Answer 1

我们假设您要查找待处理的实际天数。您可以通过运行此选择来执行此操作：

SELECT (MAX(t.status_date) - MIN(t.status_date) + 1) nodays, -- +1 is for adding a current day of pending
       t.id
  FROM table1 t
  JOIN (
        -- For every ID, find max date of not pending status or return "01/01/1900"
        SELECT t.id,
                NVL(MAX(CASE
                           WHEN t.status <> 'Pend' THEN
                            status_date
                         END),
                     to_date('01/01/1900', 'dd/mm/yyyy')) max_date
          FROM table1 t
         GROUP BY t.id
        --
        ) m
-- keep only rows that are newer than max_date
    ON t.id = m.id
   AND t.status_date > m.max_date
--
 GROUP BY t.id;

此选择将返回从第一个待处理状态到上一个待处理状态的天数。

Oracle查询计算没有天数

1 个答案: