Question

我正在尝试一个简单的事情用户点击显示的问题。单击时的链接将接收问题ID并将其作为参数传递以显示相关选项。要求用户选择一个选项，然后下一页将显示有多少人投票选择该选项（包括用户当前的决定）。我得到的错误是当我使用127.0.0.1:8000/polls/启动应用程序时，它会显示问题。然后，当我点击问题时，网址变为127.0.0.1:8000/polls/3/，这是正确的，因为3是问题ID。因此，预计会显示问题ID的选择。但它没有表现出来。错误是：

NoReverseMatch at /polls/3/

Reverse for 'results' with arguments '()' and keyword arguments '{'q_id': 3, 'c_test': 'May Be'}' not found. 1 pattern(s) tried: ['polls/(?P<q_id>[0-9]+)/(?P<c_test>\\w+)/results/$']

Request Method:     GET
Request URL:    http://127.0.0.1:8000/polls/3/
Django Version:     1.10.3
Exception Type:     NoReverseMatch
Exception Value:    

Reverse for 'results' with arguments '()' and keyword arguments '{'q_id': 3, 'c_test': 'May Be'}' not found. 1 pattern(s) tried: ['polls/(?P<q_id>[0-9]+)/(?P<c_test>\\w+)/results/$']

Exception Location:     /home/usr/.local/lib/python3.5/site-packages/django/urls/resolvers.py in _reverse_with_prefix, line 392
Python Executable:  /usr/bin/python3.5
Python Version:     3.5.2

我的代码是：

views.py

class IndexView(generic.ListView):
  template_name = "polls/index.html"
  context_object_name = "latest_question_list"
  model = Question

def get_queryset(self):
    return Question.objects.filter(
        pub_date__lte=timezone.now()
    ).order_by('-pub_date')[:5]


class DetailView(ListView):
   model = Choice
   context_object_name = "latest_choice_list"
   template_name = "polls/detail.html"

def get_queryset(self):
    print(self.args[0])
    '''Return list of choices'''
    return Choice.objects.filter(question_id=self.args[0])
    # return Choice.objects.all()

def pollvote(request, q_id, c_test):

 if c_test:
    p = Choice.objects.filter(question_id=q_id).get(choice_test=c_test)
    count = p.votes
    count += 1
    p.votes = count
    p.save()

return HttpResponseRedirect('/polls/%s/%s/results/' % c_test, q_id)

detail.html（错误表示href行的问题）

{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'polls/style.css' %}" />
{% if latest_choice_list %}
    <p>Cast your Choice</p>
<ul>


    {% for choice in latest_choice_list %}
            <li><a href="{% url 'polls:results' q_id=choice.question_id c_test=choice.choice_test%}">{{ choice.choice_test }}</a></li>


    {% endfor %}
</ul>


{% else %}
<p>No choice are available.</p>
{% endif %}

results.html：

{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'polls/style.css' %}" />
{% if latest_choice_list %}
    <p>Choices Made So Far</p>
<ul>
    {% for choice in latest_choice_list %}
    <li>{{ choice.choice_test  }} - {{ choice.votes }} </li>
    {% endfor %}
</ul>

{% else %}
<p>No choice are available.</p>
{% endif %}

urls.py

urlpatterns = [
url(r'^$', views.IndexView.as_view(), name='index'),
url(r'^([0-9]+)/$', views.DetailView.as_view(), name='detail'),    
url(r'^(?P<q_id>[0-9]+)/(?P<c_test>\w+)/results/$', views.pollvote, name='results'),]

为什么detail.html会抛出错误？为什么不采用名为arguement的两个关键字并将其传递给结果？

Answer 1

试试这个：

File -> Settings -> Languages & Frameworks -> Node.js and NPM

Django会按照给定的顺序自动分配args。

P.S。

我假设Choice模型有question_id和choice_test字段。
如果您将question_id作为整数字段作为对任何Question对象的引用，那么您可以使用django.medels的外键字段而不是这样做。 https://docs.djangoproject.com/en/1.10/topics/db/examples/many_to_one/

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