Question

So just as a thought exercise, I've been trying to code a very simple calculator that can perform functions such as addition, subtraction, multiplication, division, and powers (and eventually roots) by adding or subtracting 1 through the use of for loops and nested for loops.

I need help however with the power function(last method in code below). As multiplication requires a single nested for loop (third method shown below), i figured the power function would just be another level or two deeper. But either that is not the case, or I am not coding properly, which is the more likely of the two I suppose.

import java.util.*;

public class Main {

public static Scanner scan = new Scanner(System.in);


public static void main(String[] args) {
    Power();


}

public static void addition() {

    System.out.println("Type first number to add: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to add");
    int num2 = scan.nextInt();
    int result = num1;
    while(num2 > 0){
        num2--;
        result++;
    }

    System.out.println("The result is: " + result);

}

public static void subtraction() {

    System.out.println("Type first number to subtract: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to subtract: ");
    int num2 = scan.nextInt();
    int result = num1;
    while(num2 > 0){
        num2--;
        result--;
    }

    System.out.println("The result is: " + result);

}

public static void multiplication() {

    System.out.println("Type first number to multiply: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to multiply: ");
    int num2 = scan.nextInt();
    int result = 0;


    for(int i = num1;i>0;i--){
        for(int x = num2;x>0;x--){
            result++;
        }

    }

    System.out.println("The result is: " + result);

}

public static void division() {

    System.out.println("Type first number to divide: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to divide: ");
    int num2 = scan.nextInt();
    int result = 0;

    for(;num2>0 && num1 > num2;num2--){
        result++;
        for(;num1 > num2;num1--){

        }
    }

    System.out.println("The result is: " + result);

}

public static void Power() {

System.out.println("Type Base Number: ");
int num1 = scan.nextInt();
System.out.println("Type Exponent: ");
int num2 = scan.nextInt();
int result = 0;

for(int i = num1;i>0;i--){
    for(int x = num1;x>0;x--){
        for(int y = num2; y>0; y--){
            for(int z = num2; z>0;z--){
                result++;
            }
        }
    }

}



System.out.println("The result is: " + result);

}


}

Answer 1

你可以这样做。这有点模块化，但如果你想在一个完整的循环中，你可以将乘法函数中的代码放入幂函数。

for loop --> hello() --> getJson's inner function

组合：

let

Thought exercise on calculator based on adding or subtracting one within loops

1 个答案: