我对nodejs / typescript / promises比较陌生,所以我不确定链接promises的正确方法。
我有一个帮助类,它调用REST api来获取基于ip的地理定位。我对整个回应都不感兴趣,只对城市领域感兴趣。我如何正确地返回一个承诺,当解决时只获得城市字段?
var rest = require("axios");
const ENDPOINT = "http://freegeoip.net/json/";
@Service()
export class GeoIp {
city(ip: string): Promise<any> {
let promise: Promise<any>;
let p = rest.get(ENDPOINT + ip);
p.then((response) => {
promise = Promise.resolve(() => {return response.data["city"]});
}, (error) => {
promise = Promise.reject(() => { return error});
});
return Promise.resolve(p).then((data)=>promise);
}
}
这是我的测试代码失败,因为收到的数据对象是原始的REST响应对象
import chai = require('chai');
import {GeoIp} from "../../server/services/GeoIp";
var assert = chai.assert;
describe("GeoIp service", () => {
let geoIp: GeoIp;
beforeEach("Initialize service", () => {
geoIp = new GeoIp();
});
var IP_VALID = "137.118.222.187";
it(`Check geolocation of ${IP_VALID}`, (done) => {
let promise = geoIp.city(IP_VALID);
promise.then((data) => {
console.log(data);
assert.equal(data, "Traphill");
done();
});
});
});
答案 0 :(得分:3)
var rest = require("axios");
const ENDPOINT = "http://freegeoip.net/json/";
@Service()
export class GeoIp {
city(ip: string): Promise<any> {
return rest.get(ENDPOINT + ip).then((res) => res.data.city);
}
}
答案 1 :(得分:3)
var rest = require("axios");
const ENDPOINT = "http://freegeoip.net/json/";
@Service()
export class GeoIp {
city(ip: string): Promise<string> {
return rest
.get(ENDPOINT + ip)
.then((response) => response.data.city);
}
}
then
方法始终会返回另一个Promise
,并使Promise可以链接。
类似签名看起来也应该是Promise<string>
。