Question

我试图编写一个程序，如果连续有多个X或O，则会调用函数win。我对向上倾斜的对角线胜利有困难。我可以提供任何关于我应该改变的建议吗？提前致谢。它调用无限循环而不是返回true。

bool left_diag_win(char **board, int num_rows, int num_cols) {
    int i;

    if (board[0][0] == '*') {
        return false;
    }

    for (i = 1; i < num_rows; ++i) {
        if (board[i][i] != board[0][0]) {
            return false;
        }
    }
    return true;
}

bool right_diag_win(char **board, int num_rows, int num_cols) {
    int i;

    if (board[0][num_cols - 1] == '*') {
        return false;
    }

    for (i = 1; i < num_rows; ++i) {
        if (board[i][num_cols - i - 1] != board[0][num_cols - 1]) {
            return false;
        }
    }
    return true;
}

Answer 1

您的代码似乎正确，但您可能在其他地方遇到问题。这是一个表现如预期的例子：

#include <stdbool.h>
#include <stdio.h>

bool left_diag_win(char **board, int num_rows, int num_cols) {
    if (board[0][0] == '*') {
        return false;
    }
    for (int i = 1; i < num_rows; ++i) {
        if (board[i][i] != board[0][0]) {
            return false;
        }
    }
    return true;
}

bool right_diag_win(char **board, int num_rows, int num_cols) {
    if (board[0][num_cols - 1] == '*') {
        return false;
    }
    for (int i = 1; i < num_rows; ++i) {
        if (board[i][num_cols - i - 1] != board[0][num_cols - 1]) {
            return false;
        }
    }
    return true;
}

int main(void) {
    char *matrix1[] = { "X****", "*X***", "**X**", "***X*", "****X" };
    char *matrix2[] = { "****X", "***X*", "**X**", "*X***", "X****" };

    printf("matrix:\n");
    for (int i = 0; i < 5; i++) {
        printf("%s\n", matrix1[i]);
    }
    printf("left-diagonal: %d\n", left_diag_win(matrix1, 5, 5));
    printf("right-diagonal: %d\n\n", right_diag_win(matrix1, 5, 5));

    printf("matrix:\n");
    for (int i = 0; i < 5; i++) {
        printf("%s\n", matrix2[i]);
    }
    printf("left-diagonal: %d\n", left_diag_win(matrix2, 5, 5));
    printf("right-diagonal: %d\n\n", right_diag_win(matrix2, 5, 5));

    return 0;
}

输出：

matrix:
X****
*X***
**X**
***X*
****X
left-diagonal: 1
right-diagonal: 0

matrix:
****X
***X*
**X**
*X***
X****
left-diagonal: 0
right-diagonal: 1

如何检测X的对角线数

1 个答案: