Question

我正在尝试制作简单的java应用程序，它在屏幕上输出两个数字，用户必须输入这两个数字的总和。当我输入总和时，如果是正确的程序问我是否要继续。如果我说是，则程序输出两个新数字，当我输入正确答案时，程序不能识别答案是否正确。

如果我在程序开始时输错了答案，我希望程序一遍又一遍地询问用户解决方案，直到他输入正确的答案，但我不知道该怎么做。这是我的代码：

import java.util.Scanner;
import java.security.SecureRandom;

public class HelloWorld {
    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);
        int result = getRandomNumbers();

        int counter = 1;
        char again;

        while (counter == 1) {

            int userResult = input.nextInt();
            if (result == userResult) {
                System.out.println("You are right");
            } else {
                System.out.println("You are wrong, try again");
            }

            System.out.println("Do you want to try again? Enter y for yes or n for no");
            again = input.next().charAt(0);

            if (again == 'y') getRandomNumbers();
            else counter++;
        }

    }

    public static int getRandomNumbers() {
        SecureRandom randomNumbers = new SecureRandom();

        int fnum = 1 + randomNumbers.nextInt(9);
        int snum = 1 + randomNumbers.nextInt(9);

        System.out.println("What is " + fnum + " times " + snum);
        return fnum * snum;
    }

}

Answer 1

如果输入不是预期输入，您可以使用while循环询问用户输入新内容。

试试这个：

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    while (true) {
        int result = getRandomNumbers();
        int userResult = input.nextInt();
        while ( result != userResult) {
            System.out.println("You are wrong, try again");
            result = getRandomNumbers();
            userResult = input.nextInt();
        }
        System.out.println("You are right");

        System.out.println("Do you want to try again? Enter y for yes or n for no");

        if (input.next().charAt(0) == 'n') {
            break;
        }
    }

只有在用户说他不想继续（while (true)）时才会中断n循环。

程序无法识别解决方案

1 个答案: