我希望显示部门员工达到二十周年工作周年的日期。这就是我所拥有的:
select e.last_name, e.department_id, add_months(min(h.start_date), 240) as "20 Year Anniversary"
from employees e
inner join job_history h
on h.employee_id = e.employee_id
group by e.department_id, e.last_name;
显示:
Last_Name Department_ID 20 Year Anniversary
1 Hartstein 20 17-FEB-16
2 Bob 90 21-SEP-09
等等。但是我希望以这种格式显示日期:1月21日,1928年。我如何格式化日期?
答案 0 :(得分:2)
我认为这是你在寻找的。 select e.last_name, e.department_id,to_char(add_months(min(h.start_date), 240),'Month fmDdsp, Year') as "20 Year Anniversary"
from employees e
inner join job_history h
on h.employee_id = e.employee_id
group by e.department_id, e.last_name;
日期格式化。查看oracle的官方文档页面
http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions180.htm
class someClass:
def objFunction(self, weights):
return [self.obj1(weights), self.obj2(weights), self.obj3(weights)]
def asf(self, f):
def obj(x):
return np.max(np.array(f(x[0],x[1],x[2])))+0.00001*np.sum(f(x[0],x[1],x[2]))
res=minimize(obj,
[0.3,0.3,0.4], method='SLSQP'
,jac=ad.gh(obj)[0],options = {'disp':True, 'ftol': 1e-20,
'maxiter': 1000})
return res