Question

我试图返回共享值的列的名称。我以为我可以对数据库进行查询，并提取名称。

例如，当我的共享值为Director时，我想返回Actors和Tarantino列，因为他既是演员又是导演。

String x = "Tarantino";

String q =
        "SELECT Actors, Director, Genre, Country, Released, WHERE Actors LIKE '%"+x+"%' " +
        "AND WHERE Director LIKE  '%"+x+"%' " +
        "AND WHERE Genre LIKE  '%"+x+"%' " +
        "AND WHERE Country LIKE  '%"+x+"%' " +
        "AND WHERE Released LIKE  '%"+x+"%' " ;

然后我可以迭代光标并获取列名Director和Actors

Answer 1

要在一列中查找匹配项，请尝试以下操作：

select exists (select * from actors where director like '%"+x+"%');

要将所有四个放在一起，您可以尝试：

select q1, q2, q3, q4 
from
  (select exists (...) as q1)
  join
  (select exists (...) as q2)
  join
  (select exists (...) as q3)
  join
  (select exists (...) as q4)

取代：

你试过了吗？

    "SELECT Actors, Director, Genre, Country, Released, WHERE Actors LIKE '%"+x+"%' " +
    "AND Director LIKE  '%"+x+"%' " +
    "AND Genre LIKE  '%"+x+"%' " +
    "AND Country LIKE  '%"+x+"%' " +
    "AND Released LIKE  '%"+x+"%' " ;

请注意SELECT的工作方式，它返回所有列。您的查询应返回符合所有四个条件的行。但是，我认为你正在尝试做一些与众不同的事情。究竟是什么我不清楚。

如何返回共享值的列的名称？

1 个答案: