Question

所以我再一次，一如既往的无能为力。我有点像新手，所以这可能比我能咀嚼的多，但无论如何。该程序的要点是根据用户的输入值提供输出。如果用户没有输入正确的输入，则意味着实现输入陷阱。

我试图这样做，所以输入一个字母或一个非整数值会导致消息＆＃34;请只输入整数。＆＃34;它适用于浮点，但不适用于字母。我应该注意＆＃34;输入0到10之间的数字＆＃34;消息工作正常。此外，当用户输入“完成”时，循环应该关闭，但这只会导致＆＃34; ValueError：无法将字符串转换为浮点数：＆＃39;已完成＆＃39; ;＆＃34; 即可。

我还没有用True格式写这个，因为我更容易在循环中坚持使用这种写法。

setCount = 1
 allScore = 0
 done = False
 while not done:
   strScore = float (input ( "Enter Set#" + str(hwCount) + " score: "))
if (strScore == int (strScore) and strScore >=0 and strScore <=10):
    totalScore = totalScore + (strScore)
    setCount = setCount + 1
elif ( setScore == int (strScore) and( setScore < 0 or setScore > 10)):
    print ("Please enter a number between 0 and 10.")
elif setScore != "done":
    print ("Please enter only whole numbers.")
else:
    done = True

Answer 1

您可以立即将输入字符串转换为您读取它的同一行上的浮点数：

strScore = float (input ( "Enter HW#" + str(hwCount) + " score: "))

为了接受＆＃34;完成＆＃34;作为输入，您需要将其保留为字符串，并在完成所有输入验证后将其转换为float（或int）。

drop float()和strScore将是一个字符串。然后检查它是否等于＆＃34;完成＆＃34;。最后，将其转换为try块内的整数

print ( "Enter the homework scores one at a time. Type \"done\" when finished." )
hwCount = 1
totalScore = 0
while True:
    strScore = input ( "Enter HW#" + str(hwCount) + " score: ")
    if strScore == "done":
        break
    try:
        intScore = int(strScore)
    except ValueError:
        print ("Please enter only whole numbers.")
        continue
    if (intScore >=0 and intScore <=10):
        totalScore += intScore
        hwCount += 1
    else:
        print ("Please enter a number between 0 and 10.")

Answer 2

你应该真正清理你的代码，所有这些额外的空间都会伤害你的可读性。我建议使用PyLint（pip install pylint，pylint file.py）。

我不会过多地重构您的代码，但您需要检查“已完成”代码。在转换为浮动之前。如果有人输入无效的答案并优雅地处理它，你就会想要捕获ValueErrors。

print("Enter the homework scores one at a time. Type \"done\" when finished. Ctrl+c to quit at any time.")
hwCount = 1
totalScore = 0
try:
    while True:
        strScore = input("Enter HW#" + str(hwCount) + " score: ")
        if strScore == 'done':
            break #done
        else:
            try:
                strScore = float(strScore)
            except ValueError:
                print('Invalid input: must be a numerical score or "done"')
                continue
        if (strScore == int (strScore) and strScore >=0 and strScore <=10):
            totalScore = totalScore + (strScore)
            hwCount = hwCount + 1
        elif ( strScore == int (strScore) and( strScore < 0 or strScore > 10)):
            print ("Please enter a number between 0 and 10.")
        elif strScore != "done":
            print ("Please enter only whole numbers.")
except KeyboardInterrupt:
    pass #done

这是一个更完整的程序版本，供参考。这就是我如何重构它。

#!/usr/bin/env python3

def findmode(lst):
    bucket = dict.fromkeys(lst, 0)
    for item in lst:
        bucket[item] += 1
    return max((k for k in bucket), key=lambda x: bucket[x])

print("Enter the homework scores one at a time.")
print("Type 'done' when finished or ctrl+c to quit.")
scores = []
try:
    while True:
        strScore = input("Enter score: ")
        if strScore == 'done':
            break #done
        else:
            try:
                strScore = int(strScore)
            except ValueError:
                print('Invalid input: must be a score or "done"')
                continue
        if (0 <= strScore <= 10):
            scores.append(strScore)
        else:
            print("Please enter a valid score between 0 and 10.")
except KeyboardInterrupt:
    pass # user wants to quit, ctrl+c
finally:
    print("Total scores graded: {}".format(len(scores)))
    print("Highest score: {}".format(max(scores)))
    print("Lowest score: {}".format(min(scores)))
    print("Mean score: {}".format(sum(scores)/len(scores)))
    print("Mode score: {}".format(findmode(scores)))

输入陷阱的麻烦（除其他外）

2 个答案: