Question

我使用Alamofire和SwiftyJson连接到API。

我得到了这个JSON回复：

的

{ "contacts": [ { "id": "c200", "name": "Ravi Tamada", "email": "ravi@gmail.com", "address": "xx-xx-xxxx,x - street, x - country", "gender" : "male", "phone": { "mobile": "+91 0000000000", "home": "00 000000", "office": "00 000000" } }, { "id": "c201", "name": "Johnny Depp", "email": "johnny_depp@gmail.com", "address": "xx-xx-xxxx,x - street, x - country", "gender" : "male", "phone": { "mobile": "+91 0000000000", "home": "00 000000", "office": "00 000000" } }, { "id": "c202", "name": "Leonardo Dicaprio", "email": "leonardo_dicaprio@gmail.com", "address": "xx-xx-xxxx,x - street, x - country", "gender" : "male", "phone": { "mobile": "+91 0000000000", "home": "00 000000", "office": "00 000000" } } ] }

的

这是我的ViewController代码：

import UIKit
import Alamofire
import SwiftyJSON

class ViewController:UIViewController {
    @IBOutlet weak var tblJSON: UITableView!

    var arrRes = [[String : AnyObject]]()

    override func viewDidLoad() {
        super.viewDidLoad()
        getRequest()
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func getRequest() {
        Alamofire.request("http://api.androidhive.info/contacts").responseJSON { (responseData) -> Void in
            if ((responseData.result.value) != nil) {
                let swiftyJsonVar = JSON(responseData.result.value!)

                if  let resData = swiftyJsonVar["contacts"].arrayObject {
                    self.arrRes = resData as! [[String : AnyObject]]
                }

                if self.arrRes.count > 0 {
                    self.tblJSON.reloadData()
                }
            }
        }
    }

    //MARK: tableView
    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return arrRes.count
    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell : UITableViewCell = tableView.dequeueReusableCell(withIdentifier: "Cell")!
        var dict = arrRes[indexPath.row]
        cell.textLabel?.text = dict["name"] as? String
        cell.detailTextLabel?.text = dict["email"] as? String
        return cell
    }

}

我在UITableView上显示结果时遇到问题。谁能帮我？谢谢！

Answer 1

您需要像这样实施UITableViewDataSource和UITableViewDelegate

class ViewController:UIViewController, UITableViewDataSource, UITableViewDelegate

并在viewDidLoad中，您需要将DataSource和Delegate分配给您的tableView，如下所示

override func viewDidLoad() {
    super.viewDidLoad()
    tblJSON.dataSource = self
    tblJSON.delegate = self
    getRequest()
}

TableView不显示带有来自API调用的JSON数据的文本

1 个答案: