Question

我有一个php数组如下：

Array
(
    [0] => Array
        (
            [EmployeeAttendance] => Array
                (
                    [attendance_id] => 1
                    [arrival_datetime] => 2016-11-01 03:31:00
                    [status] => Present
                )
        )

    [1] => Array
        (
            [EmployeeAttendance] => Array
                (
                    [attendance_id] => 2
                    [arrival_datetime] => 2016-11-03 06:31:00
                    [status] => Present
                )

        )

    [2] => Array
        (
            [EmployeeAttendance] => Array
                (
                    [attendance_id] => 3
                    [arrival_datetime] => 2016-11-06 07:31:00 
                    [status] => Present  
                )
        )

    [3] => Array
        (
            [EmployeeAttendance] => Array
                (
                    [attendance_id] => 4
                    [arrival_datetime] => 2016-11-08 19:31:00
                    [status] => Present
                )
        )

    [4] => Array
        (
            [EmployeeAttendance] => Array
                (
                    [attendance_id] =>5
                    [arrival_datetime] => 2016-11-10 08:00:00
                    [status] => Present
                )
        )
)

在这个数组中，我们可以看到从'2016-11-01'到'2016-11-10'的出勤详情，有些日期在这里缺失，如'2016-11-02'，'2016-11- 04'，'2016-11-05'，'2016-11-07'和'2016-11-09'。现在我想查看“2016-11-01”到“2016-11-10”之间的日期缺失日期，并将缺少的日期插入到数组中，状态为“缺席”。请给出一些建议。

Answer 1

首先收集所有日期，排序，生成第一个之间的日期范围，然后丢失插入

$data = [

    [
        'EmployeeAttendance' => [
            'attendance_id'=>1
            ,'arrival_datetime'=>'2016-11-01 03:31:00'
            ,'status'=>'Present'
        ]
    ]
,[
        'EmployeeAttendance' => [
            'attendance_id'=>1
            ,'arrival_datetime'=>'2016-11-05 03:31:00'
            ,'status'=>'Present'
        ]
    ]
    ,[
 'EmployeeAttendance' => [
        'attendance_id'=>1
        ,'arrival_datetime'=>'2016-11-11 03:31:00'
        ,'status'=>'Present'
    ]
]
];

$dates = [];
foreach ($data as $x => $d) {
    $dates[] = substr($d['EmployeeAttendance']['arrival_datetime'],0,10);
}
sort($dates);
$period = new DatePeriod(
    new DateTime($dates[0]),
    new DateInterval('P1D'),
    new DateTime(end($dates))
);
foreach ($period as $d) {
    $key = $d->format('Y-m-d');
    if (!in_array($key,$dates)) {
        $data[] = [
            'EmployeeAttendance' => [
                 'arrival_datetime'=>$key
                ,'status'=>'absent'
            ]
        ];
    }
}
print_r($data);

Answer 2

您好，您也可以试试这个

    $a = array(array('EmployeeAttendance'=>array('attendance_id'=>1,'arrival_datetime'=>'2016-11-01 03:31:00','status'=>'Present')),array('EmployeeAttendance'=>array('attendance_id'=>2,'arrival_datetime'=>'2016-11-03 04:31:00','status'=>'Present')),array('EmployeeAttendance'=>array('attendance_id'=>3,'arrival_datetime'=>'2016-11-07 07:31:00','status'=>'Present')),array('EmployeeAttendance'=>array('attendance_id'=>4,'arrival_datetime'=>'2016-11-09 05:31:00','status'=>'Present')));
    foreach($a as $key=>$data){
        $presentDates[] =  date("j", strtotime($data['EmployeeAttendance']['arrival_datetime']));// will give array of present dates array(1,3,7,9);
    }
    $first = reset($presentDates);
    $last = end($presentDates);
    $total = range($first,$last); // will give all dates between start and end
    $absentArr = array_diff($total, $presentDates); // will give missing dates array(2,4,5,6,8)
    foreach($absentArr as $value){
    $a[]['EmployeeAttendance'] = array('arrival_datetime'=>'2016-11-'.$value,'status'=>'Absent');
    }
  print_r($a);

在php数组中找到丢失的日期

2 个答案: