Question

我有来自ajax调用的ajax json数据，响应是json_encode。

public function editimg()`enter code here`
     {
     $config['image_library'] = 'gd2';
      $id=$this->input->post('hiddenimgid');     
      $config['upload_path'] = './assets/img/movies';
      $config['allowed_types'] = 'gif|jpg|png';
      $config['max_size']   = '150';
      $config['max_width']  = '199';
      $config['max_height']  = '199';
    //echo "hii";die;
    // print_r($config);die;
        $this->load->library('upload', $config);
        if ( ! $this->upload->do_upload())
        { 
            //echo "not uploaded";die;
            $error = array('error' => $this->upload->display_errors());
$data['message'] = "Image Cannot be Uploaded,Try Again !!";
            $data['error']=$error;

        $this->index_one($data);

        } //if

        else
        {
            //echo "hii";die;
            $config['image_library'] = 'gd2';
            $image_data         = $this->upload->data();
            $filename           = $image_data['file_name'];
            $source_path        = 'assets/img/movies/'.$filename ;
            $new_image_path     = 'assets/img/movies/'.$image_data['raw_name'].'_thumb'.$image_data['file_ext']; //name of resized image
            $target_path        = 'assets/img/movies/';
            $thumb['image_library'] = 'gd2';
            $thumb['source_image']  = $source_path;
            $thumb['new_image']     = $target_path;
            $thumb['create_thumb']  = TRUE;
            $thumb['maintain_ratio'] = TRUE;
            $thumb['width']  = 140;
            $thumb['height'] = 200;
            //print_r($thumb);die;
            //$this->load->library('image_lib', $config);
            $this->load->library('image_lib', $thumb); 



                     if ( !$this->image_lib->resize())
                     { 
                        //echo "hii";die;
                        //$this->session->set_flashdata('errors', $this->image_lib->display_errors('', '')); 
                        $this->session->set_flashdata('errors', $error= $this->image_lib->display_errors('', '')); 
                        print_r($error);die;
                     }
                    else
                    { 
                        //echo "hii";die;
                        //print_r($thumb);die;
                        $data=array(

                        'image'=>$new_image_path
                        );
                        //print_r($new_image_path);die;
                        if($this->movies_model->updateMovies($data,$id))         
                        {
                            $data['message'] = "Movies added successfully !!";
                            //$this->index_one($data);
                            redirect("movies/index", 'refresh');
                            //print_r($thumb);die;
                        }
                        else
                        {
                        $data['message'] = "not_uploaded !!";   
                        $this->index_one($data);
                        }
                    }
         }
}

我正在访问它并放入数据表中。我有脚本代码

$user=array('id'=>$val->id,'username'=>$name,'contactno'=>$val->contact_no);
echo json_encode($user);

我无法在datatable中获取json数据。请帮忙

Answer 1

使用datatable ajax语法

$('#example').dataTable( {
  "ajax": {
    "url": "<?php echo base_url(); ?>list/people",
    "type": "POST"
  }
});

PHP：

$user =[];
$content_array = $this->list_model->users_list(); 

foreach($content_array as $key=>$val) { 
 $id = $val->id;
 $name = $val->user_name;
 $contact=>$val->contact_no;
 $user[]=array('id'=>$val->id,'username'=>$name,'contactno'=>$v‌al->contact_no);
}   
echo json_encode(array("data"=>$user));

Answer 2

您可以将ajax DataTable用于此

$(document).ready(function() {
    $('#example').DataTable({
      "processing": true,
      "serverSide": true,
      "ajax":{
          url : '<?php echo base_url(); ?>list/people'
          type: "post",  // method  , by default get,
          data : function ( d ) {
                //any data that you want to send with request
                /*
                  var dt_params = {'myKey' : 'MyValue'};
                  $.extend(d, dt_params);
                */
             },
          complete : function(response){
              // you will receive data here
          }
      }
    });
  });

来自服务器的数据与

相同

$用户=阵列（＆＃39; ID＆＃39; =＆GT; $ val-＆GT; ID＆＃39;用户名＆＃39; =＆GT; $名称，＆＃39; contactno＆＃39; =＆GT ; $ val-＆GT; contact_no）; echo json_encode（$ user）; exit;

Answer 3

您的数组必须采用此格式

$user = array(
    array('id'=>$val->id,'username'=>$name,'contactno'=>$val->contact_no)
);

因为您正在使用数据表。

数据表属性＆＃39;数据＆＃39;在javascript中必须是这样的格式

[{
    'id': 1,
    'username': 'my username',
    'contact_no': 'my contact no.'
}]

数据不在数据表中，数据来自ajax调用

3 个答案: