Question

我正在尝试在1个PHP代码中创建2个表单堆叠。但表格根本无法提交。它只是坐在那里而没有将这个表格传递给action =“...”

这里是第一种形式的编码（注册）

<form id="RegForm" class="form" action="PHP/Enter_New.php" method="post">
<!-- Progress Bar -->
<ul id="ProgressBar">
    <li class="active">Access Code</li>
    <li>Account Setup</li>
    <li>User Agreement</li>
</ul>

<!-- Fieldsets -->
<fieldset>
    <h2 class="fs-title">Are you lost?</h2>
    <h3 class="fs-subtitle">Get your access code before enter!!</h3>
    <input type="text" name="invite" class="invite field" placeholder="Access Code" onkeyup="checkAvAccess()" autocomplete='off' required />
    <br />
        <img src="/Images/Gif/Checking.gif" id="loaderIcon-access" style="display:none" />
        <span id="availability-status-access"></span>
    <br />
    <input type="button" name="login" class="action-button" id="toLog" value="Login" />
    <input type="button" name="next" class="next action-button" id="access" value="Next" disabled="disabled" />
</fieldset>
<fieldset>
    <h2 class="title">Account setup</h2>
    <h3 class="subtitle">Login information</h3>
    <input type="text" name="username" class="username field" id="regUsername" placeholder="Username" onkeyup="checkAvReg()" autocomplete='off' />
        <img src="/Images/Gif/Checking.gif" id="loaderIcon-reg" style="display:none" />
        <span id="availability-status-reg"></span>

    <input type="password" name="password" class="password field" id="password" placeholder="Password" required />
        <div class="pwstrength_viewport_progress"></div>
    <input type="button" name="previous" class="previous action-button" value="Previous" />
    <input type="button" name="next" class="next action-button" id="logInfo" value="Next" disabled="disabled" />
</fieldset>
<fieldset>
    <h2 class="fs-title">User Agreement</h2>
    <h3 class="fs-subtitle">By signup at our website... </h3>        
    <input type="button" name="previous" class="previous action-button" value="Previous" />
    <input type="submit" name="submit" class="submit action-button" id="subRegister" value="Submit" disabled="disabled"/>
</fieldset>

注册表关闭后，那里没有其他代码..登录代码后的下一个代码

<form id="LoginForm" class="form" name="login" action="PHP/Redirrect_to.php" method="post">
<fieldset>
    <h2 class="fs-title">Enter Website</h2>
    <h3 class="fs-subtitle">Please login to continue!!</h3>
    <input type="text" name="username" class="username field" id="login" placeholder="Username" onkeyup="checkAvLogin()" autocomplete='off' required />
        <img src="/Images/Gif/Checking.gif" id="loaderIcon-login" style="display:none">
        <span id="availability-status-login"></span>
    <input type="password" name="password" class="password field" placeholder="Password" required />
        <div class="pwstrength_viewport_progress"></div>
    <input type="button" name="register" class="action-button" id="toReg" value="Register" />
    <input type="submit" name="submit" class="submit action-button" id="subLogin" value="Submit" formaction="PHP/Redirrect_to.php" formmethod="post" disabled="disabled" />
</fieldset>

请注意，在onkeyup =“..”后，js会删除提交输入上的禁用值。值= true

你会看到那里有很多下一个和前一个因为我使用多步骤基本形式。 Here the original code。我从js

中删除了返回false值

Answer 1

永远不要将提交按钮命名为“提交”

<input type="submit" name="submit" ... />  <-- bad name

<input type="submit" name="anyNameButSubmit" ... />  <-- good name

Form submit button will not submit when name of button is "submit"

输入类型提交未将流程传递给操作

1 个答案: