Question

我有三张桌子

service_cats（id - cat_name）
service_sub_cats（id - cat_id - sub_cat_name）
sub_cat_contents（id - sub_cat_id - title - content）

和我建立了这种关系

serviceCat

public function serviceSubCat()
    {
        return $this->hasMany('ServiceSubCat');
    }

serviceSubCat

public function ServicesCat()
    {
        return $this->belongsTo('ServiceCat', 'cat_id');
    }

    public function ssContent()
    {
        return $this->hasMany('SubCatContent');
    }

subCatContent

public function ssCat()
    {
        return $this->belongsTo('ServiceSubCat', 'sub_cat_id');
    }

我需要从三个表中获取葡萄数据才能使用它们。

这是我的控制器

public function show($id)
    {
        $serCat = ServiceCat::where('id', $id)->first();
        $getId = $serCat->sub_status;
        if ($getId == 1) {
            $subCats = ServiceSubCat::with('ssContent')->where('cat_id', $id)->get();
            //dd($subCats);
            return View::make('portal.services.servicesDetailsList', compact('serCat', 'subCats'));
        } else {
            return View::make('portal.services.servicesDetails');
        }
    }

现在我收到错误

未找到专栏

我需要获取cat_name，sub_cat_name，title，content

Answer 1

确保您的关系定义为：

<强> serviceCat

public function serviceSubCat()
{
    return $this->hasMany('ServiceSubCat', 'cat_id');
}

<强> serviceSubCat

public function ServicesCat()
{
    return $this->belongsTo('ServiceCat', 'cat_id');
}

public function ssContent()
{
  return $this->hasMany('SubCatContent', 'sub_cat_id');
}

<强> subCatContent

public function ssCat()
{
  return $this->belongsTo('ServiceSubCat', 'sub_cat_id');
}

您的控制器

public function show($id)
{
    $serCat = ServiceCat::where('id', $id)->with('serviceSubCat.ssContent')->first();
    $getId = $serCat->sub_status;
    if ($getId == 1) {
        return View::make('portal.services.servicesDetailsList', compact('serCat'));
    } else {
        return View::make('portal.services.servicesDetails');
    }
}

然后在您的视图中，您可以这样做：

{{ $serCat->cat_name }}
@foreach ($serCat->serviceSubCat as $ser)
    {{ $ser->sub_cat_name }}
    @foreach ($ser->ssContent as $subCatContent)
        {{ $subCatContent->title }}
        {{ $subCatContent->content }}
    @endforeach
@endforeach

Laravel：使用雄辩的三个表格中选择

1 个答案: