Question

im trying to pass a url to fetch data for android JSON.

网址是： fetch_cat_url =“xxx / get_product_details.php？task_name = get_cat＆amp; cat_name =”+ cat_name;

where cat_name="Books & More"
now when i pass this url.. it goes like

xxxxx/get_product_details.php?task_name=get_cat&cat_name=Books & More

in my sql file
switch($_GET["cat_name"])
        {
            case "Fashion":
            $sql = "SELECT * FROM `category` where c_name IN (\"Men\",\"Women\" ,\"Baby & Kids\") ";
            break;

            case "Home & Living":
            $sql = "SELECT * FROM `category` where c_name IN (\"Kitchenware\", \"Home Furnishing\", \"Home Decoratives\", \"Furniture\") ";
            break;

            case "Books & More":
            $sql = "SELECT * FROM `category` where c_name IN (\"Academic Text\", \"Literature & Fiction\", \"Non Fiction\", \"Self Help\", \"Children & Young Adult\", \"Competitive Exam\") ";
            break;

            case "Automotives":
            $sql = "SELECT * FROM `category` where c_name IN (\"Car Accessories\", \"Helmets & Accessories\", \"Car & Vehical Electronics\", \"Car Freshners\", \"Spare Parts\") ";
            break;
        }

now for & the data is not returned in json.. but it returns for rest all categories...

时尚和汽车的数据回归，但书籍和家庭没有数据

Answer 1

从客户端cat_name传递json时，请确保json字符串应按此编码。

String jsonString = Uri.EncodeDataString(json)

现在只需将jsonString传递给服务器.. 可能会有所帮助。

在sql中使用＆符号时如何传递和获取数据

1 个答案: