我想用代码来获取它们。不与谷歌评论,因为人们需要有一个谷歌帐户。我查看了schema.org,但我得不到它。
所以我如何在我的片段中获得星星
答案 0 :(得分:4)
您应该使用AggregateRating:
<script type="application/ld+json">
{
"@context" : "http://schema.org",
"@type" : "LocalBusiness",
"name" : "My Company",
"url" : "http://www.mycompany.com/",
"telephone" : "(+33) 1 23 45 67 89",
"email" : "info@mycompany.com",
"address" : {
"@type" : "PostalAddress",
"streetAddress" : "1 Rue de la Place",
"addressLocality" : "Paris",
"postalCode" : "75000"
},
"aggregateRating" : {
"@type" : "AggregateRating",
"ratingValue" : "4.2",
"bestRating" : "5",
"ratingCount" : "100"
},
"openingHours": "Mo-Su 00:00-00:00"
}
</script>
上面的代码段应该放在结束</html>
标记之前,并且应该根据100个评分显示得分为4.2 / 5