Question

我的项目有点问题。事实证明，当名字或姓氏的值中包含“ñ”时，查询结果不会返回任何内容这是我的代码

的config.php：

<?php
   ini_set('mssql.charset', 'UTF-8');
   header('content-type: text/html; charset=utf-8');
   $serverName = "192.168.1.21"; /* IP add of db Server */
   $connection = array("Database" => "db", "UID" => "?", "PWD" => "***");
   $conn = sqlsrv_connect($serverName, $connection);

if(!$conn){
echo "Connection could not be established.";
die(print_r(sqlsrv_errors(), true));
}
?>

更改为MyQuery：

$idnumber = $_POST["idnum"];
$response = array();
$query2 = "SELECT cLName, cFName, cMName, cQualifier FROM student WHERE cIDNO = '$idnumber'";

try{
    $stmt2 = sqlsrv_query($conn, $query2);
}
catch(PDOExeption $ex){
    $response["Success"] = 0;
    $response["message"] = "Database Error!";
    die(json_encode($response));
}
$row2 = sqlsrv_fetch_array($stmt2, SQLSRV_FETCH_ASSOC);

    if($row2){
        $response["Success"] = 1;
        $response["message"] = "Data available";
        $last_name = $row2["cLName"];
        $first_name = $row2["cFName"];
        $qualify = $row2["cQualifier"];

        $first_name = html_entity_decode(htmlentities($first_name));
        $last_name = html_entity_decode(htmlentities($last_name));

        $name = $first_name." ".$last_name." ".$qualify;

        $response["Name"] = $name;

        echo json_encode($response);
    }

    else{
        $response["Success"] = 0;
        $response["message"] = "Database Error!";
        die(json_encode($response));
    }

我查看了这些页面： 1，2，3，etc.

但我不知道为什么这会发生在我的程序中。

数据库中的示例： cLName = "Española", cFName = "Edgar", cQualifier = "Jr."
输出 "Name":"Edgar Jr."
同时： cLName = "Agustin", cFName = "Florence", cQualifier = "Jr."
输出 "Name":"Florence Agustin Jr."

想法？请？

注意：我无权更改或更改数据库中的任何内容。

Answer 1

我认为它的编码错误mssql conest不是UTF-8模式，

如果以下是ISO-8859-1的内存，我做了什么，并且utf8_encode缺少输出是OP得到的，但是utf8_encode是正确的

<?php


$row = ['cLName' => "Española", 'cFName' => "Edgar", 'cQualifier' => "Jr."];

$last_name  = utf8_encode($row["cLName"]);
$first_name = $row["cFName"];
$qualify    = $row["cQualifier"];

$first_name = html_entity_decode(htmlentities($first_name));
$last_name = html_entity_decode(htmlentities($last_name));

$name = $first_name." ".$last_name." ".$qualify;

$response["Name"] = $name;
$enc = json_encode($response,JSON_UNESCAPED_UNICODE);

print_r($name);
print_r($response);
print_r($enc);

无法正确查询（MSSQL - PHP - JSON）

1 个答案: