我正在尝试获取数据并在tableView中显示。因为我必须在viewDidLoad中发送请求。但是加载我的数据需要花费很多时间,所以我需要以异步的方式完成它。 任何建议或建议。?
- (void)viewDidLoad {
//------castApi----//
[super viewDidLoad];
[[self tableView2]setDelegate:self ];
[[self tableView2]setDataSource:self];
array=[[NSMutableArray alloc]init];
NSString *castString = [NSString stringWithFormat:@"https://api.themoviedb.org/3/movie/%@/credits?api_key=c4bd81709e87b12e609433c49",movieIDinString];
NSURL *url=[NSURL URLWithString:castString];
NSURLRequest *request=[NSURLRequest requestWithURL:url];
connection=[NSURLConnection connectionWithRequest:request delegate:self];
if (connection){
webData= [[NSMutableData alloc]init];
}
}
答案 0 :(得分:0)
试试这个
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.themoviedb.org/3/movie/%@/credits?api_key=c4bd81709e87b12e609433c49",movieIDinString]];
NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url];
NSOperationQueue *queue = [[NSOperationQueue alloc] init];
[NSURLConnection sendAsynchronousRequest:urlRequest queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error)
{
}];