Question

我的老师让我写一个函数，通过使用另一个字母来计算字符串的出现次数。例如：

>>>problem3("all is quiet on the western front", "tqe")
>>>["t=4", "q=1", "e=4"]

然而我只能这样做：

>>>problem3("all is quiet on the western front", "tqe")
>>>[4, 1, 4]

这是我的代码：

def problem3(myString, charString):
    return [myString.count(x) for x in (charString)]

我如何以这种格式获得[＆＃34; t = 4＆＃34;，＆＃34; q = 1＆＃34;，＆＃34; e = 4＆＃34;]？

Answer 1

所以你被要求非常具体地格式化它并且你很接近，只需要格式化结果：

def problem3(myString, charString):
    return ['{}={}'.format(x, myString.count(x)) for x in charString]

>>> problem3("all is quiet on the western front", "tqe")
['t=4', 'q=1', 'e=4']

分别计算字符串中的多个字符

1 个答案: