Question

我有两个阵列：

array:5 [▼
  0 => "1 Oct 2016"
  1 => "2 Oct 2016"
  2 => "3 Oct 2016"
  3 => "4 Oct 2016"
  4 => "5 Oct 2016"
]

和

array:5 [▼
  0 => "29 Sep 2016"
  1 => "30 Sep 2016"
  2 => "1 Oct 2016"
  3 => "2 Oct 2016"
  4 => "3 Oct 2016"
]

我需要将它们合并为一个按日期排序的方法，以获得类似的结果：

array:7 [▼
  0 => "29 Sep 2016"
  1 => "30 Sep 2016"
  2 => "1 Oct 2016"
  3 => "2 Oct 2016"
  4 => "3 Oct 2016"
  5 => "4 Oct 2016"
  6 => "5 Oct 2016"
]

我该怎么做？

Answer 1

您可以使用array_merge（获取一个数组），array_unique（以消除重复项）和usort（以正确的顺序获取它们）来执行此操作：

$c = array_unique(array_merge($a, $b));
usort($c, function($a, $b) { return strtotime($a) - strtotime($b); });

在eval.in上看到它。

Answer 2

<?php

function _sort($a, $b)
{
    $a = DateTime::createFromFormat('d M Y', $a);
    $b = DateTime::createFromFormat('d M Y', $b);

    if ($a == $b) return 0;

    return ($a < $b) ? -1 : 1;
}

$a =  [
  0 => "1 Oct 2016",
  1 => "2 Oct 2016",
  2 => "3 Oct 2016",
  3 => "4 Oct 2016",
  4 => "5 Oct 2016",
];

$b = [
  0 => "29 Sep 2016",
  1 => "30 Sep 2016",
  2 => "1 Oct 2016",
  3 => "2 Oct 2016",
  4 => "3 Oct 2016",
];

$merged = array_merge($a, $b);
# sort
usort($merged, '_sort');

print_r($merged);

特定数组与php中的日期合并

2 个答案: