我在Powershell中有一个哈希表,看起来像这样($hash_dates.GetEnumerator() | sort -Property name
):
11/1/2016 12:00:00 AM 5
11/2/2016 12:00:00 AM 3
11/4/2016 12:00:00 AM 2
密钥是DateTime类型。
我正在运行一个for循环来捕获所有日期(仅日期,时间无关紧要因此都是午夜)并根据日期提取哈希表中的每个值。代码:
$startdate = (get-date).AddDays(-30)
$today = get-date -format G
for($i = $startdate; $i -lt $today; $i=$i.AddDays(1))
{
$z = $i -split " "
$z = [datetime]$z[0]
$z = Get-Date $z -format G
"Comparing $z to: "
$hash_dates.Keys | ? { $hash_dates[$_] -eq $z }
}
我使用-format G
和split
来确保格式匹配。但循环永远不会找到任何结果(即使它循环通过2016年11月1日等)。我错过了什么吗?
答案 0 :(得分:3)
由于哈希表键是[datetime]
个对象,根本不需要使用日期字符串 和字符串解析:
$today = (Get-Date).Date # Note the .Date part, which omits the time portion
$startdate = $today.AddDays(-30)
# Note the change from -lt to -le to include today
for($i = $startdate; $i -le $today; $i = $i.AddDays(1))
{
# Note that `echo` is an alias for `Write-Output`, which is the default,
# so no need for an explicit output command.
"Looking for $i..."
# Simply try to access the hashtable with $i as the key, which
# either outputs nothing ($null), or outputs the value for that key.
$hash_dates.$i
}
重新echo
/ Write-Output
/默认输出:请注意,您的状态消息将成为您的数据(输出)流,这可能是不受欢迎的。
请考虑使用Write-Information
代替。
这是一个简化解决方案,展示了PowerShell的表现力:
$today = (get-date).Date
# Construct an array with all dates of interest.
$dates = -30..0 | % { $today.AddDays($_) } # % is a built-in alias for ForEach-Object
# Pass the entire array as the hashtable "subscript", which returns
# the values for all matching keys while ignoring keys that don't exist.
$hash_dates[$dates]
答案 1 :(得分:0)
这是你想要的吗?
$startdate = (get-date).AddDays(-30)
$today = get-date -format G
for($i = $startdate; $i -lt $today; $i=$i.AddDays(1))
{
$z = $i -split " "
$z = [datetime]$z[0]
Echo "Comparing $z to: "
$z = Get-Date $z
$hash_dates.$z
}