Question

2个月大的程序员在这里。

尝试创建一个接受3个学生分数的程序。输出将是他们取得的名称，标记和等级。我的问题是，我只希望程序接受3个特定名称（例如Lisa，Lorraine，Susan），如果其他人输入其他名称，我希望它显示“无效”

另外如您所见，我只能在用户输入正确的标记时显示学生姓名。（“Hi Lisa，你的标记是”+标记）所以如果我输入另一个名字和相同的标记，它将显示相同的输出。我该如何解决？

CODE：

package studentmarks;

import java.util.Scanner;
public class StudentMarks 

{


  public static void main(String[] args) 
  {
    int mark;
    int passmark = 50;

    String name;

    Scanner sc = new Scanner(System.in);

    System.out.println(" Enter your name "); //ask user for name
    name = sc.nextLine(); //accept input

    System.out.println("Now please enter your mark");   //ask user to enter mark
    mark = sc.nextInt(); //accept mark


    if (mark == 60) //if mark = 60
    {
        System.out.println(" Hi Lisa, your mark is " + mark ); //output
    }

    if (mark ==12)
    {
        System.out.println("Hi Lorraine, you scored a mark of " + mark);  
    }

    if (mark== 50) 
    {
        System.out.println("Hi susan, you have scored a mark of " + mark);
    }

     if (mark < passmark)
    {
        System.out.println("FAIL");
    }

      if (mark >= passmark)
    {
        System.out.println("PASS");
    }


 }

感谢您抽出宝贵时间阅读本文。

Answer 1

您需要验证步骤。您永远不会根据有效的值检查输入的name。试试这个：

public static void main(String[] args) 
{
    // Initial setup stuff here
    // ...

    System.out.println("Enter your name:"); //ask user for name
    name = sc.nextLine(); //accept input

    boolean validName = validateName(name);
    if(validName)
    {
        System.out.println("Now please enter your mark:"); //ask user to enter mark
        mark = sc.nextInt(); //accept mark

        System.out.println("Hi " + name + ". You scored a " + mark + ".");

        String result = "pass";
        if (mark < passmark)
        {
           result = "fail";
        }
        System.out.println("You " + result + ".");
    }
    else
    {
        System.out.println(name + " is not a valid entry.");
    }
}

public boolean validateName(String name)
{
    if(name.equalsIgnoreCase("Lisa") || name.equalsIgnoreCase("Lorraine") || name.equalsIgnoreCase("Susan")
    {
        return true;
    }

    return false;
}

我如何只接受用户的三个特定名称？

1 个答案: