Question

我试图直接将图像插入到oracle数据库表中。在我的数据库中，我总是得到[BLOB - 0B]。它不会将图像插入表格中。我也没有得到任何错误。

<html>
<form action="save_img.php" method="post" enctype="multipart/form-data">
     <input type="file" name="image"/>
      <input type="submit"/>
</form>
</html>


<?php
include('config.php');

$fp = fopen($_FILES['image']['tmp_name'],'rb'); //read binary

try{         
     $stmt=$con->prepare("insert into images(photo) values(?)");    
     $stmt->bindParam(1,$fp,PDO::PARAM_LOB);
     $con->errorInfo();
     $stmt->execute();
}

catch(PDOEception $e){
    echo($e->getMessage()); 
}

?>

Answer 1

我终于做到了：

<?php

   include '../conexao_oracle.php';

   $db->beginTransaction(); // VERY IMPORTANT !
   $stmt = $db->prepare(
       "INSERT INTO images (photo) ".
       "VALUES (EMPTY_BLOB()) ".
       "RETURNING photo INTO :photo");
   $stmt->bindParam(':photo', $blob, PDO::PARAM_LOB);
   $blob = fopen($_FILES['image']['tmp_name'],'rb');
   $stmt->execute();
   $db->commit();

pdo直接将图像插入oracle数据库 - 插入BLOB - 0B

1 个答案: