Question

在我的xml中，我有许多ID和REF属性。

简化：

<library>
 <book ID="123">
   <author ref="33"></author>
   <Info>Vulpes Vulpes, Canis Lupus</info>
   <about>Programming</about>
 </book>

 <author ID="33">
  <firstname>John</firstname>
  <lastname>McLovin</lastname>
 </author>
</library>

所以我想使用Xquery使用book下的REF属性来提取有关作者的信息。

for $x in library/book 
where $x/about = "programming"
return data ($x/library/book/author/@ref)

使用这种方法，我提取重新编号33.但我想要ref =“33”指向的数据，它位于ID =“33”下。我希望将firstname和lastname作为结果。

这可能吗？如果不是这样，怎么可能？

Answer 1

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Xquery：如何从REF / ID中提取信息

1 个答案: