Question

我是Android的新手，我建立活动点击提交按钮从五个edittext获取数据作为json并转换为AES加密并将其存储在本地当我刷新或重新启动活动我想要获取文件解密并自动填充到5编辑文本...加密对我来说很好，但解密不会......帮帮我

 protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
         e1 = (EditText)findViewById(R.id.editText1);
        e2 = (EditText)findViewById(R.id.editText2);
        e3 = (EditText)findViewById(R.id.editText3);
        e4 = (EditText)findViewById(R.id.editText4);
        e5 = (EditText)findViewById(R.id.editText5);
        final JSONObject obj = new JSONObject();
        sub = (Button)findViewById(R.id.button);
        final File file = new File(Environment.getExternalStorageDirectory().getAbsolutePath(), "Outer_Folder");
        file.mkdir();            // store and fetch file from storage...
        f1  = new File(file,"null"+".txt");
        f2  = new File(fileD,"null"+".txt");
        try {
            SecureRandom srm = SecureRandom.getInstance("SHA1PRNG");
            srm.setSeed("no one can read".getBytes());
            KeyGenerator kg = KeyGenerator.getInstance("AES");
            kg.init(128,srm);
            sec = kg.generateKey();
           bb1 = sec.getEncoded();
        } catch (NoSuchAlgorithmException e) {
            e.printStackTrace();
        }
        if (f1.exists()){
            File file3 = new File(Environment.getExternalStorageDirectory().getAbsolutePath(), "Outer_Folder");
            f4  = new File(file3,"null"+".txt");
            int size = (int)f4.length();
            contents = new byte[size];
            try {
                 bufferedInputStream = new BufferedInputStream(new FileInputStream(f4));
                try {
                    bufferedInputStream.read(contents);
                    bufferedInputStream.close();
                    String dd = new String(contents);
                    SecretKeySpec sdf = new SecretKeySpec(bb1,"AES");
                    Cipher cv = Cipher.getInstance("AES");
                    cv.init(Cipher.DECRYPT_MODE,sdf);
                    decodefile = cv.doFinal(dd.getBytes());         // aes decryption not working 
                    String ggg = new String(decodefile);
                    Toast.makeText(getApplicationContext(),ggg,Toast.LENGTH_SHORT).show();
                    JSONObject jsonObj = new JSONObject(ggg);
                    v1=jsonObj.getString("one");
                    v2=jsonObj.getString("two");                 // when enter the activity json filled by decryped file
                    v3=jsonObj.getString("three");
                    v4=jsonObj.getString("four");
                    v5=jsonObj.getString("five");
                    e1.setText(v1);
                    e2.setText(v2);
                    e3.setText(v3);
                    e4.setText(v4);
                    e5.setText(v5);
                } catch (IOException e) {
                    e.printStackTrace();
                } catch (NoSuchAlgorithmException e) {
                    e.printStackTrace();
                } catch (InvalidKeyException e) {
                    e.printStackTrace();
                } catch (NoSuchPaddingException e) {
                    e.printStackTrace();
                } catch (JSONException e) {
                    e.printStackTrace();
                }
                 catch (BadPaddingException e) {
                    e.printStackTrace();
                } catch (IllegalBlockSizeException e) {
                    e.printStackTrace();
                }

            } catch (FileNotFoundException e) {
                e.printStackTrace();
            } }else {
            Toast.makeText(getApplicationContext(),"con't read",Toast.LENGTH_LONG).show();
        } sub.setOnClickListener(new View.OnClickListener() {
            @TargetApi(Build.VERSION_CODES.KITKAT)
            @Override
            public void onClick(View v) {
                s1=e1.getText().toString();
                s2=e2.getText().toString();
                s3=e3.getText().toString();
                s4=e4.getText().toString();
                s5=e5.getText().toString();
                try {
                    obj.put("one", s1);
                    obj.put("two", s2);
                    obj.put("three", s3);          //converting json 
                    obj.put("four", s4);
                    obj.put("five", s5);
                    if (f1.exists()){ //
                        f1.delete();
                    }
                     vv = obj.toString();
                    new execute();

                    try {
                        SecretKeySpec sksep = new SecretKeySpec(bb1,"AES");
                        Cipher cp = Cipher.getInstance("AES");
                        cp.init(Cipher.ENCRYPT_MODE,sksep);
                        encobyte = cp.doFinal(vv.getBytes());  // aes encryption  - working
                        FileOutputStream uu = null;
                        uu = new FileOutputStream(f1);
                        uu.write(encobyte);
                        oo = new String(encobyte);
                        Toast.makeText(getApplicationContext(),oo,Toast.LENGTH_LONG).show();
                    } catch (NoSuchAlgorithmException e) {
                        e.printStackTrace();
                    } catch (NoSuchPaddingException e) {
                        e.printStackTrace();
                    } catch (InvalidKeyException e) {    //
                        e.printStackTrace();
                    } catch (BadPaddingException e) {
                        e.printStackTrace();            //
                    } catch (IllegalBlockSizeException e) {
                        e.printStackTrace();
                    }

                } catch (IOException e) {
                    e.printStackTrace();
                } catch (JSONException e) {
                    e.printStackTrace();
                }

Answer 1

这可能是序列化/反序列化错误，尽管很难知道没有任何错误或其他信息。

在将数据序列化为持久存储之前，请尝试在encobyte阵列上使用十六进制或Base64编码。在对其进行解密之前，对检索到的数据dd执行相应的解码操作。

如何在存储中解密（AES）本地存储的加密文件

1 个答案: