在roslyn

Question

我试图使用Roslyn从我的CS文件中提取部分代码，我遇到了以下问题。

我的C＃文件代码：

    class ConditionalCompilationCode
    {
#if Condition2
            int test2=0; 
#endif
#if Condition1
            int test1=0; 
#endif

        public static void Main1(string[] args)
        {
            int test = 0;
#if Condition1
            test = 1;
#else
            test =2;
#endif

#if Condition2
            test =3;
#else
            test = 4;
#endif

        }
#if Condition2
            private void testmethod1()
        {
            test2 = 1;
        }
#endif
#if !Condition2
        private void testmethod2()
        {
            test1 = 1;
        }
#endif
#if Condition1
        private void testmethod3()
        {
            test1 = 1;
        }
#endif
#if !Condition1
            private void testmethod4()
        {
            test2 = 1;
        }
#endif
    }
}

我的roslyn代码：

string fileContent = File.ReadAllText(fileName);

SyntaxTree syntaxTree = CSharpSyntaxTree.ParseText(fileContent);

var syntaxRootNode = syntaxTree.GetRoot();
            if (syntaxRootNode.GetFirstToken().Kind() == SyntaxKind.None)
                return;
            foreach (NamespaceDeclarationSyntax namespaceSyntax in syntaxRootNode.DescendantNodes().OfType<NamespaceDeclarationSyntax>().ToArray())
            {

                IEnumerable<SyntaxNode> nodeList = namespaceSyntax.ChildNodes();
                string className = null;
                foreach (SyntaxNode syntaxNode in nodeList)
                {
                    SyntaxKind kind = syntaxNode.Kind();
                    switch (kind)
                    {
                        case SyntaxKind.ClassDeclaration:
                            UpdateClassSignature(syntaxNode as TypeDeclarationSyntax);                            
                            break;
                        case SyntaxKind.EnumDeclaration:

                            break;
                        case SyntaxKind.InterfaceDeclaration:

                            break;
                        case SyntaxKind.StructDeclaration:

                            break;

                    }

                }

            }

    private void UpdateClassSignature(TypeDeclarationSyntax classDeclarationSyntax)
        {

            foreach (MemberDeclarationSyntax member in classDeclarationSyntax.Members)
            {
                SyntaxKind kind = member.Kind();
                switch (kind)
                {
                    case SyntaxKind.FieldDeclaration:
                        break;
                    case SyntaxKind.PropertyDeclaration:
                        break;
                    case SyntaxKind.MethodDeclaration:
                    case SyntaxKind.ConstructorDeclaration:
                    case SyntaxKind.DestructorDeclaration:
                        break;
                    case SyntaxKind.IndexerDeclaration:
                        ExtractIndexer(member as IndexerDeclarationSyntax, classSign);
                        break;
                    case SyntaxKind.DelegateDeclaration:
                        //TODO: Add Delegate Support.
                        break;
                    case SyntaxKind.OperatorDeclaration:
                    case SyntaxKind.ConversionOperatorDeclaration:
                        //Skip.
                        //TODO: Need to add operator suport.
                        break;
                    case SyntaxKind.EventFieldDeclaration:
                        //TODO: Add support to event.
                        break;
                    case SyntaxKind.EventDeclaration:
                        //TODO: Add support to event.
                        break;
                    case SyntaxKind.EnumDeclaration:
                        break;
                    case SyntaxKind.ClassDeclaration:
                        break;
                    case SyntaxKind.StructDeclaration:
                        break;
                    default:
                        break;
                }
            }
        }

在使用roslyn处理上述CS文件时，classDeclarationSyntax.Members包含以下三个值：

1. MethodDeclarationSyntax MethodDeclaration

   public static void Main1(string[] args)
   {
       int test = 0;
       #if Condition1
       test = 1;
       #else
       test =2;
       #endif
   
      #if Condition2
       test =3;
      #else
       test = 4;
     #endif
   
   }
   

2. MethodDeclarationSyntax MethodDeclaration

   private void testmethod2()
   {
       test1 = 1;
   }
   

3. MethodDeclarationSyntax MethodDeclaration

   private void testmethod4()
   {
       test2 = 1;
   }
   

我的项目单独有“Condition1”指令。你能帮助我仅在条件单独有“Condition1”时才能获得代码吗？

提前致谢。

Answer 1

您需要传递一个调用 08048ce1 <func4>: //not entirely sure what's happening here but it might be a binary search? 8048ce1: 83 ec 1c sub $0x1c,%esp 8048ce4: 89 5c 24 10 mov %ebx,0x10(%esp) 8048ce8: 89 74 24 14 mov %esi,0x14(%esp) 8048cec: 89 7c 24 18 mov %edi,0x18(%esp) 8048cf0: 8b 74 24 20 mov 0x20(%esp),%esi 8048cf4: 8b 5c 24 24 mov 0x24(%esp),%ebx 8048cf8: 85 f6 test %esi,%esi 8048cfa: 7e 2b jle 8048d27 <func4+0x46> 8048cfc: 83 fe 01 cmp $0x1,%esi 8048cff: 74 2b je 8048d2c <func4+0x4b> 8048d01: 89 5c 24 04 mov %ebx,0x4(%esp) 8048d05: 8d 46 ff lea -0x1(%esi),%eax 8048d08: 89 04 24 mov %eax,(%esp) 8048d0b: e8 d1 ff ff ff call 8048ce1 <func4> 8048d10: 8d 3c 18 lea (%eax,%ebx,1),%edi 8048d13: 89 5c 24 04 mov %ebx,0x4(%esp) 8048d17: 83 ee 02 sub $0x2,%esi 8048d1a: 89 34 24 mov %esi,(%esp) 8048d1d: e8 bf ff ff ff call 8048ce1 <func4> 8048d22: 8d 1c 07 lea (%edi,%eax,1),%ebx 8048d25: eb 05 jmp 8048d2c <func4+0x4b> 8048d27: bb 00 00 00 00 mov $0x0,%ebx 8048d2c: 89 d8 mov %ebx,%eax 8048d2e: 8b 5c 24 10 mov 0x10(%esp),%ebx 8048d32: 8b 74 24 14 mov 0x14(%esp),%esi 8048d36: 8b 7c 24 18 mov 0x18(%esp),%edi 8048d3a: 83 c4 1c add $0x1c,%esp 8048d3d: c3 ret 的{​​{1}}来将您要定义的符号传递给解析器。