Question

如何在数据对象内部使用不一致的密钥解析json数据？2016年和2015年的密钥名称不是固定的并且是随机的。数据对象中可以有更多数组，具有随机密钥名称。我可以创建一个模型类这样的json数据？我可以用gson吗？

Answer 1

您无法使用未知密钥制作模型。如果你想制作模型，那么你必须知道键名。是的，您可以像这样阅读动态json

JSONObject data = response.getJSONObject("data");// here response is server response
Iterator keys = data.keys();

while(keys.hasNext()) {
    // loop to get the dynamic key
    String key = (String)keys.next();

    // get the value of the dynamic key
    JSONArray value = data.getJSONArray(key);

    // do your more stuff here
}

Answer 2

使用以下代码：

    JSONObject jsonO = new JSONObject(jsonString);
    int responseCode=jsonO.getInt("responseCode");
    String responseMessage=jsonO.getString("responseMessage");

    JSONObject jsondata=jsonO.getJSONObject("data");

    for (String key : jsondata.keys()) {
        Object o = jsondata.get(key)
        if (o instanceof JSONArray) {
            JSONArray jsonA = (JSONArray) o;
            int muberOfItems = jsonA.length();
            for (int i = 0; i < muberOfItems; i++) {
                //parse your Data
            }
        } else { //must be some other value }

        }
    }

Answer 3

You can also try this Simple :

    String response = "YOUR RESPONSE";

    JSONObject resObj = new JSONObject(response);
    JSONObject jsonObject = resObj.getJSONObject("data");
    HashMap<String, String> hashMap2015 = new HashMap<>();
    HashMap<String, String> hashMap2016 = new HashMap<>();

    if (jsonObject.has("2015")) {
        JSONArray jsonArray2015 = jsonObject.getJSONArray("2015");

        for (int i = 0; i < jsonArray2015.length(); i++) {
            JSONObject jsonObject1 = jsonArray2015.getJSONObject(i);
            hashMap2015.put(jsonObject1.getString("key"), jsonObject1.getString("value"));
        }
    }

    if (jsonObject.has("2016")) {
        JSONArray jsonArray2016 = jsonObject.getJSONArray("2016");
        for (int i = 0; i < jsonArray2016.length(); i++) {
            JSONObject jsonObject1 = jsonArray2016.getJSONObject(i);
            hashMap2016.put(jsonObject1.getString("key"), jsonObject1.getString("value"));
        }
    }

Answer 4

 JSONObject object = new JSONObject(response);
 try{
    JSONObject data = new JSONObject(object.getJSONObject("data"));
    JSONArray arr2015 = new JSONArray(data);
    for(int ePos = 0; ePos < arr2015.lenght; ePos ++){
           JSONObject insideArr = jsonArray.getJSONObject(ePos);
           String key = insideAr.getString("key")
           String value = insideAr.getString("value")
           //add this values to your object

    }
    JSONArray arr2016 = new JSONArray(data);
    for(int ePos = 0; ePos < arr2016.lenght; ePos ++){
           JSONObject insideArr = jsonArray.getJSONObject(ePos);
           String key = insideAr.getString("key")
           String value = insideAr.getString("value")
            //add this values to your object
    }

}catch (JSONException e){
    return e.getMessage();
}

Answer 5

您可以使用GSON解析此问题。这对我有用，

POJO课程

ParsedData.java

public class ParsedData {

    private Integer responseCode;
    private String responseMessage;
    Map<String, List<List<Item>>> data = new HashMap<String, List<List<Item>>>();

    public Integer getResponseCode() {
        return responseCode;
    }

    public void setResponseCode(Integer responseCode) {
        this.responseCode = responseCode;
    }

    public String getResponseMessage() {
        return responseMessage;
    }

    public void setResponseMessage(String responseMessage) {
        this.responseMessage = responseMessage;
    }

    public Map<String, List<List<Item>>> getData() {
        return data;
    }

    public void setData(Map<String, List<List<Item>>> data) {
        this.data = data;
    }
}

Item.java

public class Item {
    private String key;
    private String value;

    public String getKey() {
        return key;
    }

    public void setKey(String key) {
        this.key = key;
    }

    public String getValue() {
        return value;
    }

    public void setValue(String value) {
        this.value = value;
    }
}

GSON代码

String data = "{\n" +
        "\t\"responseCode\": 200,\n" +
        "\t\"responseMessage\": \"Operation succeeded successfully\",\n" +
        "\t\"data\": {\n" +
        "\t\t\"2016\": [\n" +
        "\t\t\t[{\n" +
        "\t\t\t\t\"key\": \"Id\",\n" +
        "\t\t\t\t\"value\": \"101_202704916\"\n" +
        "\t\t\t}, {\n" +
        "\t\t\t\t\"key\": \"amount\",\n" +
        "\t\t\t\t\"value\": \"1.48\"\n" +
        "\t\t\t}, {\n" +
        "\t\t\t\t\"key\": \"Type\",\n" +
        "\t\t\t\t\"value\": \"gchgch\"\n" +
        "\t\t\t}],\n" +
        "\t\t\t[{\n" +
        "\t\t\t\t\"key\": \"Id\",\n" +
        "\t\t\t\t\"value\": \"101_202704916\"\n" +
        "\t\t\t}, {\n" +
        "\t\t\t\t\"key\": \"amount\",\n" +
        "\t\t\t\t\"value\": \"1.48\"\n" +
        "\t\t\t}, {\n" +
        "\t\t\t\t\"key\": \"Type\",\n" +
        "\t\t\t\t\"value\": \"gchgch\"\n" +
        "\t\t\t}]\n" +
        "\t\t],\n" +
        "\t\t\"2015\": [\n" +
        "\t\t\t[{\n" +
        "\t\t\t\t\t\"key\": \"Id\",\n" +
        "\t\t\t\t\t\"value\": \"101_202704916\"\n" +
        "\t\t\t\t}, {\n" +
        "\t\t\t\t\t\"key\": \"amount\",\n" +
        "\t\t\t\t\t\"value\": \"1.48\"\n" +
        "\t\t\t\t}, {\n" +
        "\t\t\t\t\t\"key\": \"Type\",\n" +
        "\t\t\t\t\t\"value\": \"gchgch\"\n" +
        "\t\t\t\t}\n" +
        "\n" +
        "\t\t\t],\n" +
        "\t\t\t[{\n" +
        "\t\t\t\t\t\"key\": \"Id\",\n" +
        "\t\t\t\t\t\"value\": \"101_202704916\"\n" +
        "\t\t\t\t}, {\n" +
        "\t\t\t\t\t\"key\": \"amount\",\n" +
        "\t\t\t\t\t\"value\": \"1.48\"\n" +
        "\t\t\t\t}, {\n" +
        "\t\t\t\t\t\"key\": \"Type\",\n" +
        "\t\t\t\t\t\"value\": \"gchgch\"\n" +
        "\t\t\t\t}\n" +
        "\n" +
        "\t\t\t]\n" +
        "\t\t]\n" +
        "\t}\n" +
        "}";

ParsedData data1 = new Gson().fromJson(data, ParsedData.class);
for (String key : data1.getData().keySet()) {
    List<List<Item>> items = data1.getData().get(key);
    for (List<Item> item : items) {
        for (Item item1 : item) {
            Log.e("TAG", item1.getKey() + " : " + item1.getValue());
        }
    }
}

使用随机密钥解析json数据（密钥在整个过程中保持不变）

5 个答案: