Question

$result3=$this->hrdb->select(array('concat(eb.first_name," ",eb.middle_name, " ",eb.last_name,"") as emp_name','eb.id','pp.emp_id','pp.gross_monthly','pp.amount as net_amount','pp.payslip_id','eor.dep_id'))
                    ->where('pp.emp_id' not_in                    (select(array('pp.gross_monthly','pp.emp_id','pp.amount as net_amount','pp.payslip_id'))),Null,FALSE)
                    ->from('payroll_payments as pp')
                    ->join('employee_basic as eb','pp.emp_id=eb.id','left')
                    ->join('employee_org as eor','pp.emp_id=eor.emp_id','left')
                    ->order_by($_field, $params['_sort_direction'])
                    ->where(array('pp.npyear'=>$params['nep_year'],'pp.npmonth'=>$params['nep_month2']))
                    ->get()
                    ->result();

是我写的查询，但问题出现了

解析错误：语法错误，意外的T_STRING /var/www/html/vianet_db/htdocs/addons/shared_addons/modules/hrm/models/payslip_m.php 在第558行

Answer 1

使用concat(eb.first_name." ".eb.middle_name." ".eb.last_name."") as emp_name并检查。从查询中删除'引用，只需添加字段名称即可。而不是'eb.id','pp.emp_id'，请使用eb.id,pp.emp_id。对选择部分中的所有字段执行此操作，不需要数组ID。

Answer 2

您需要在SELECT中添加第二个可选参数FALSE（也请先选择），以免自动转义字符。

$subqueryResult = //your subquery result in array

$result3=$this->hrdb->select(array('concat(eb.first_name," ",eb.middle_name, " ",eb.last_name,"") as emp_name','eb.id','pp.emp_id','pp.gross_monthly','pp.amount as net_amount','pp.payslip_id','eor.dep_id'), FALSE)
                    ->from('payroll_payments as pp')
                    ->join('employee_basic as eb','pp.emp_id=eb.id','left')
                    ->join('employee_org as eor','pp.emp_id=eor.emp_id','left')
                    ->where_not_in('pp.emp_id', $subqueryResult)
                    ->where(array('pp.npyear'=>$params['nep_year'],'pp.npmonth'=>$params['nep_month2']))
                    ->order_by($_field, $params['_sort_direction'])
                    ->get()
                    ->result();

使用ci中不在查询中的位置

2 个答案: