仅打印＆＃34;程序中出错！＆＃34;

Question

#include <stdio.h>

int main(){

    int age;
    char gender;
    printf("Are you male or female (m/f)?");
    scanf("%c",&gender);
    printf("Enter your age:");
    scanf("%d",&age);
    printf("\n");

    if(gender=="m"){
        if(age>=0 && age<=55){
         printf("You are a man in your best years!\n");
        }
        else if (age>=56 && age<=100){
            printf("You are a wise man!\n");}
        else{
    printf("An error occurred in the program!");}
    }
    else if(gender=="f"){
    if(age>=0 && age<=55){
         printf("You are a beauty!\n");
        }
        else if (age>=56 && age<=100){
            printf("You look young for your age!\n");}
        else{
    printf("An error occurred in the program!");}

    }
    else{
    printf("An error occurred in the program!");}
    return 0;
}

程序无法正常运行。它只打印最后的其他语句打印，即＆＃34;程序中出错！＆＃34;。我还尝试将所有条件放在相同的小括号中

喜欢：

if(gender=="f"&& age>=0 && age<=55)) 

但仍未输出预期结果。

Answer 1

您正在将char与string文字(gender == "m")进行比较。双引号用于字符串。在m (gender == 'm')和f (gender == 'f')周围使用单引号。