Question

我尝试在Doctrine 2中的场景中实现以下内容：

有车手驾驶车辆
在这些比赛中，车辆可能发生意外

这在Skipper中如下所示：

导出到基于Doctrine 2注释的实体，这看起来像这样（Getter和setter被剪断）：

Driver.php

<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 */
class Driver
{
    /**
     * @ORM\Id
     * @ORM\Column(type="bigint")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $Id;

    /**
     * @ORM\Column(type="text", nullable=false)
     */
    private $Name;
}

Vehicle.php

<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 */
class Vehicle
{
    /**
     * @ORM\Id
     * @ORM\Column(type="bigint")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $Id;

    /**
     * @ORM\Column(type="text", nullable=false)
     */
    private $Name;
}

Race.php

<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 */
class Race
{
    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $Id;

    /**
     * @ORM\Column(type="text", nullable=false)
     */
    private $Name;
}

Accident.php

<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 */
class Accident
{
    /**
     * @ORM\Column(type="text", nullable=false)
     */
    private $Description;

    /**
     * @ORM\ManyToOne(targetEntity="Racing\Entity\RacingVehicle")
     * @ORM\JoinColumns({
     *     @ORM\JoinColumn(name="Racing_Vehicle_Driver_Id", referencedColumnName="Driver_Id", nullable=false),
     *     @ORM\JoinColumn(name="Racing_Vehicle_Vehicle_Id", referencedColumnName="Vehicle_Id", nullable=false)
     * })
     */
    private $RacingVehicle;

    /**
     * @ORM\Id
     * @ORM\ManyToOne(targetEntity="Racing\Entity\Race")
     * @ORM\JoinColumn(name="Race_Id", referencedColumnName="Id", nullable=false)
     */
    private $Race;
}

RacingVehicle.php

<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 */
class RacingVehicle
{
    /**
     * @ORM\Column(type="integer", nullable=false)
     */
    private $Startnumber;

    /**
     * @ORM\Id
     * @ORM\ManyToOne(targetEntity="Racing\Entity\Driver")
     * @ORM\JoinColumn(name="Driver_Id", referencedColumnName="Id", nullable=false)
     */
    private $Driver;

    /**
     * @ORM\Id
     * @ORM\ManyToOne(targetEntity="Racing\Entity\Vehicle")
     * @ORM\JoinColumn(name="Vehicle_Id", referencedColumnName="Id", nullable=false)
     */
    private $Vehicle;
}

测试样本如下所示：

// Get the entity manager
$sservicelocator = $this->getServiceLocator();
$entitymanager = $sservicelocator->get('doctrine.entitymanager.orm_default');

// Create a driver
$driver = new Driver();
$driver->setName("Michael Schumacher");
$entitymanager->persist($driver);

// Create a vehicle
$vehicle = new Vehicle();
$vehicle->setName("Ferrari");
$entitymanager->persist($vehicle);

// Create a race
$race = new Race();
$race->setName("Monaco");
$entitymanager->persist($race);

// Create a racing vehicle
$racingvehicle = new RacingVehicle();
$racingvehicle->setDriver($driver);
$racingvehicle->setVehicle($vehicle);
$racingvehicle->setStartnumber(42);
$entitymanager->persist($racingvehicle);

// Create an accident
$accident = new Accident();
$accident->setRace($race);
$accident->setRacingVehicle($racingvehicle);
$entitymanager->persist($accident); // <-------------- Error line

// Flush
$entitymanager->flush();

一旦我试图坚持这次事故，我就会收到这个错误：

The given entity of type 'Racing\Entity\Accident' (Racing\Entity\Accident@0000000072a5fbd400007f1c433b761e) has no identity/no id values set. It cannot be added to the identity map.

所以我的问题：如何创建一个自己的实体（事故），将RacingVehicle和Race作为主键，同时真正拥有自己的PHP类实体（我可以创建多对多的关系，但在那种情况下我赢了＆＃ 39;拥有自己的意外实体。）

Answer 1

我认为您可以将Driver和Vehicle添加为RacingVehicle的ID。然后Accident看起来像这样：

<?php
namespace Racing\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 */
class Accident
{
    //...

    /**
     * @ORM\Id
     * @ORM\ManyToOne(targetEntity="Racing\Entity\Driver")
     * @ORM\JoinColumn(name="Driver_Id", referencedColumnName="Id", nullable=false)
     */
    private $Driver;

    /**
     * @ORM\Id
     * @ORM\ManyToOne(targetEntity="Racing\Entity\Vehicle")
     * @ORM\JoinColumn(name="Vehicle_Id", referencedColumnName="Id", nullable=false)
     */
    private $Vehicle;

    /**
     * @ORM\Id
     * @ORM\ManyToOne(targetEntity="Racing\Entity\Race")
     * @ORM\JoinColumn(name="Race_Id", referencedColumnName="Id", nullable=false)
     */
    private $Race;

    //...
}

这意味着您将获得三列的复合键。您现在可以使用Driver_Id列和Vehicle_Id列来解决事故中的RacingVehicle。

不确定是否可以直接映射它，因为它可能会导致索引冲突（因为Driver_Id的索引与Driver表中的标识符和{{1}的索引相关联} Vehicle_Id表中的标识符）但您可以在生命周期事件中加载或创建Vehicle的代理。

如何创建基于多个唯一键

1 个答案: