对不起,我已经阅读了很多帖子来理解这一点并最终让自己感到困惑!
我有2个阵列:
数组1:
Array (
[0] => Array ( [ID] => SI012348 [Date] => 06/01/2016 [Month] => 1 [Tier1] => 2.188875 [Tier2] => [Tier3] => [Tier4] => [Delivery] => 0 )
[1] => Array ( [ID] => SI012351 [Date] => 06/01/2016 [Month] => 1 [Tier1] => 2.139 [Tier2] => 0 [Tier3] => 0 [Tier4] => 0 [Delivery] => 0 )
[2] => Array ( [ID] => SI012387 [Date] => 14/01/2016 [Month] => 1 [Tier1] => 0.201 [Tier2] => 0 [Tier3] => 0 [Tier4] => 0 [Delivery] => 0 )
)
数组2 :(包含所有带运费的发票)
Array (
[SI000005] => 25
[SI000010] => 15
[SI000054] => 20
[SI000069] => 0
[SI000074] => 20
[SI000076] => 16
)
我需要更新SI00000x匹配的阵列1,并将阵列2中的值推送到阵列1中的[Delivery]值。
我确信这很简单,但我尝试的一切都需要一个年龄或崩溃!
请帮忙!
答案 0 :(得分:3)
你可以使用它(注意ampersand):
foreach ($arr1 as &$rec) {
if (isset($arr2[$rec['ID']])) $rec['Delivery'] = $arr2[$rec['ID']];
}
答案 1 :(得分:1)
试试这个(使用参考)
foreach ($array1 as &$a1) {
if(isset($array1[$a1['ID']])) $a1['Delivery'] = $array1[$a1['ID']];
}
答案 2 :(得分:0)
foreach ($array1 as &$a1) {
if (isset($array2[$a1['ID']])) {
$a1['Delivery'] = $array2[$a1['ID']];
}
}