我是currentyl尝试使用BOOST_SPIRIT_DEFINE/DECLARE/INSTANTIATE
将我的提升精神x3解析器分成不同的_def和.cpp文件,但我一直收到链接错误。
HERE是我的解析器,它是分开的。
链接器错误读取
<artificial>:(.text.startup+0xbb): undefined reference to `bool kyle::parser::impl::parse_rule<__gnu_cxx::__normal_iterator<char*, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >, boost::spirit::x3::context<boost::spirit::x3::skipper_tag, boost::spirit::x3::char_class<boost::spirit::char_encoding::standard, boost::spirit::x3::space_tag> const, boost::spirit::x3::unused_type>, boost::spirit::x3::unused_type const>(boost::spirit::x3::rule<kyle::parser::impl::identifier_class, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> >, false>, __gnu_cxx::__normal_iterator<char*, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >&, __gnu_cxx::__normal_iterator<char*, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > > const&, boost::spirit::x3::context<boost::spirit::x3::skipper_tag, boost::spirit::x3::char_class<boost::spirit::char_encoding::standard, boost::spirit::x3::space_tag> const, boost::spirit::x3::unused_type> const&, boost::spirit::x3::unused_type const&)'
我做错了什么?我怎样才能使我的例子有效?
config.hpp:
#include <boost/spirit/home/x3.hpp>
namespace kyle{
namespace parser{
namespace x3 = boost::spirit::x3;
typedef std::string::const_iterator iterator_type;
typedef x3::phrase_parse_context<x3::ascii::space_type>::type context_type;
}
}
literals.cpp:
#include "literals_def.hpp"
#include "config.hpp"
#include <boost/spirit/home/x3.hpp>
namespace kyle {
namespace parser {
namespace impl {
BOOST_SPIRIT_INSTANTIATE(identifier_type, iterator_type, context_type);
}
}
}
literals_def.hpp:
#include <boost/spirit/home/x3.hpp>
#include "literals.hpp"
namespace kyle {
namespace parser {
namespace impl {
namespace x3 = boost::spirit::x3;
const identifier_type identifier = "identifier";
auto const identifier_def = x3::alpha >> *x3::alnum;
BOOST_SPIRIT_DEFINE(identifier)
}
impl::identifier_type identifier(){
return impl::identifier;
}
}
}
literals.hpp:
#include <boost/spirit/home/x3.hpp>
namespace kyle{
namespace parser{
namespace impl {
namespace x3 = boost::spirit::x3;
struct identifier_class;
typedef x3::rule<identifier_class, std::string> identifier_type;
BOOST_SPIRIT_DECLARE(identifier_type)
}
impl::identifier_type identifier();
}
}
main.cpp:
#include "literals.hpp"
#include <iostream>
template<typename Parser>
bool test(std::string str, Parser&& p, bool full_match = true)
{
auto in = str.begin();
auto end = str.end();
bool ret = boost::spirit::x3::phrase_parse(in, end, p, boost::spirit::x3::space);
ret &= (!full_match || (in == end));
return ret;
}
int main(){
auto b = test("fobar", kyle::parser::identifier());
std::cout << b << std::endl;
}
答案 0 :(得分:6)
两点:
您将上下文定义为
foreign_key_constraint/3
但是,您尝试使用typedef x3::phrase_parse_context<x3::space_type>::type context_type;
而不是x3::space
来调用它。
提示位于您未包含的错误消息中:
x3::ascii::space
的/home/sehe/custom/boost/boost/spirit/home/x3/nonterminal/rule.hpp:116: undefined reference to 'bool kyle::parser::impl::parse_rule<__gnu_cxx::__normal_iterator<char const*, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >, boost::spirit::x3::context<boost::spirit::x3::skipper_tag, boost::spirit::x3::char_class<boost::spirit::char_encoding::standard, boost::spirit::x3::space_tag> const, boost::spirit::x3::unused_type>, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >(boost::spirit::x3::rule<kyle::parser::impl::identifier_class, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> >, false>, __gnu_cxx::__normal_iterator<char const*, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > >&, __gnu_cxx::__normal_iterator<char const*, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> > > const&, boost::spirit::x3::context<boost::spirit::x3::skipper_tag, boost::spirit::x3::char_class<boost::spirit::
强>char_encoding::standard
迭代器类型被推断为, boost::spirit::x3::space_tag> const, boost::spirit::x3::unused_type> const&, std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> >&)'
,而不是std::string::iterator
。修复它或不要始终使用std::string::const_iterator
:
<强> Live On Melpon 强>
为后代
config.hpp:
auto
literals.cpp:
#include <boost/spirit/home/x3.hpp>
namespace kyle{
namespace parser{
namespace x3 = boost::spirit::x3;
typedef std::string::const_iterator iterator_type;
typedef x3::phrase_parse_context<x3::space_type>::type context_type;
}
}
literals_def.hpp:
#include "literals_def.hpp"
#include "config.hpp"
#include <boost/spirit/home/x3.hpp>
namespace kyle { namespace parser { namespace impl {
BOOST_SPIRIT_INSTANTIATE(identifier_type, iterator_type, context_type);
} } }
literals.hpp:
#include <boost/spirit/home/x3.hpp>
#include "literals.hpp"
namespace kyle {
namespace parser {
namespace impl {
namespace x3 = boost::spirit::x3;
const identifier_type identifier = "identifier";
auto const identifier_def = x3::alpha >> *x3::alnum;
BOOST_SPIRIT_DEFINE(identifier)
}
impl::identifier_type identifier(){
return impl::identifier;
}
}
}
main.cpp:
#include <boost/spirit/home/x3.hpp>
namespace kyle{
namespace parser{
namespace impl {
namespace x3 = boost::spirit::x3;
struct identifier_class;
typedef x3::rule<identifier_class, std::string> identifier_type;
BOOST_SPIRIT_DECLARE(identifier_type)
}
impl::identifier_type identifier();
}
}
CMakeLists.txt:
#include "literals.hpp"
#include <iostream>
template<typename Parser>
bool test(std::string const& str, Parser p, std::string& output, bool full_match = true)
{
auto in = str.begin();
auto end = str.end();
bool ret = boost::spirit::x3::phrase_parse(in, end, p, boost::spirit::x3::space, output);
ret &= (!full_match || (in == end));
return ret;
}
int main(){
std::string s;
auto b = test("fobar", kyle::parser::identifier(), s);
std::cout << b << ": " << s << std::endl;
}
答案 1 :(得分:4)
除了回答之外,我还要补充一点:
您需要对您声明的内容和实际使用内容非常准确。 X3允许任何类型的可能类型,但链接器不允许。
这里有一个提示:当发生链接器错误时,在BOOST_SPIRIT_INSTANTIATE之后,声明如下内容:
int x = context_type{};
这将是一个错误,是的,因为context_type无法转换为int。但是,该错误也会为您提供上下文的确切类型。将它与链接器错误进行比较,您将看到错误。