Question

我有一张表my_table看起来像 -

+---------------------+---------------------+
| phone               | status              |
+---------------------+---------------------+
| 019                 | NI                  |
+---------------------+---------------------+
| 019                 | DROP                |
+---------------------+---------------------+
| 019                 | SALE                |
+---------------------+---------------------+
| 018                 | B                   |
+---------------------+---------------------+
| 016                 | DROP                |
+---------------------+---------------------+

我的查询

SELECT DISTINCT(phone) AS phone FROM my_table WHERE status NOT IN ('NI','SALE','B')

RESULT

+---------------------+
| phone               |
+---------------------+
| 019                 |
+---------------------+
| 016                 |
+---------------------+

但我想在下面

+---------------------+
| phone               |
+---------------------+
| 016                 |
+---------------------+

我的查询结果中不需要手机019。因为电话019已经有NI和SALE状态。

如何通过更新我的查询来实现？

Answer 1

我使用反连接模式：

 SELECT t.phone
   FROM my_table t
   LEFT
   JOIN my_table r
     ON r.phone = t.phone
    AND r.status IN ('NI','SALE','B')
  WHERE r.phone IS NULL
 GROUP BY t.phone

这样想。我们可以获得所有phone值的列表...

我们可以获得状态为“NI”，“SALE”或“B”的phone值列表。

诀窍是从“全部”列表中返回phone的值，不包括第二个列表中的值。

反连接只是一种选择;还有其他查询模式将返回相同的结果。

其他一些选项是NOT EXISTS子查询...

 SELECT t.phone
   FROM my_table t
  WHERE NOT EXISTS ( SELECT 1
                       FROM my_table r
                      WHERE r.phone = t.phone
                        AND r.status IN ('NI','SALE','B')
                   )
 GROUP BY t.phone

另一种选择是条件聚合......

 SELECT t.phone
   FROM my_table t
 GROUP BY t.phone
HAVING IFNULL(SUM(t.status IN ('NI','SALE','B')),0) = 0

Answer 2

SELECT DISTINCT phone
FROM yourtable AS a
WHERE NOT EXISTS (SELECT 1
                    FROM yourtable AS b
                   WHERE a.phone = b.phone
                     AND b.status in ('NI', 'SALES', 'B'));

这具有额外的好处，即假设手机上有一个索引，它将始终使用索引。

Answer 3

不确定你想要的逻辑。

在这里，我会找到没有NI，没有SALES且没有B的电话。

 SELECT phone
 FROM my_table 
 GROUP BY phone
 HAVING COUNT(CASE WHEN status = 'NI' THEN 1 END) = 0
    AND COUNT(CASE WHEN status = 'SALES' THEN 1 END) = 0
    AND COUNT(CASE WHEN status = 'B' THEN 1 END) = 0

Answer 4

我通过更新Query

修复了我的问题

PROPER QUERY

SELECT DISTINCT(phone) FROM my_table WHERE status NOT IN ('NI','SALE','B') AND status IN ('DROP')

以上query对我有用，执行时间也减少了。

如何更新此MySQL查询以获取正确的数据？

4 个答案: