Question

$assignment = assignment::find(Crypt::decrypt($id));
$assignment_details = $assignment->raw_plan()->groupBy('flag')->get();

我想在laravel

中关注此查询的结果

SELECT GROUP_CONCAT(name) AS 'names' FROM `raw_plans` where `assignment_id` = 1 GROUP BY`flag`

请建议我如何在laravel中使用GROUP_CONCAT

Answer 1

您可以使用关系作为查询构建器来获取结果：

$assignment_details = $assignment->raw_plan()
                                ->select(DB::raw('group_concat(name) as names'))
                                ->where('assignment_id', 1)
                                ->groupBy('flag')
                                ->get();

<强>更新

在select中使用table_name.*获取所有字段。

$assignment_details = $assignment->raw_plan()
                                ->select('raw_plans.*', DB::raw('group_concat(name) as names'))
                                ->where('assignment_id', 1)
                                ->groupBy('flag')
                                ->get();

Answer 2

shoieb有些正确，但您应该在访问DB:raw()

中的列名之前提供表名

你应该试试这个：

$data = DB::table('raw_plans')
            ->select(DB::raw("group_concat(raw_plans.name)"))
            ->groupBy('flag')
            ->where('assignement_id',1)
            ->get();

希望这有帮助。

Answer 3

尝试使用以下代码

$data = DB::table('raw_plans')
            ->select(DB::raw("GROUP_CONCAT(name SEPARATOR '-') as `names`"))
            ->groupBy('flag')
           ->where('assignement_id',1)
            ->get();

Answer 4

试试这个

$sql = "SELECT GROUP_CONCAT(name) AS 'names' FROM `raw_plans` where  `assignment_id` = 1 GROUP BY`flag`";

  $info = DB::select(DB::raw($sql));

如何在laravel中使用GROUP_CONCAT

4 个答案: