Question

您正在处理聊天应用程序，我想对新邮件进行排序，并根据时间保留历史记录顺序。

例如，我在这样的数组中有聊天消息

[{"user":"a", "msg":"Hi ", "msg_count":1, "unix_time":"1474476800000"}
{"user":"b", "msg":"Hi ", "msg_count":1, "unix_time":"1478776800000"}
{"user":"c", "msg":"Hi ", "msg_count":5, "unix_time":"1479276800000"}
{"user":"d", "msg":"Hi ", "msg_count":1, "unix_time":"1478416800000"}
{"user":"e", "msg":"Hi ", "msg_count":3, "unix_time":"1478476800000"}]

我如何使用＆＃34; msg_count＆＃34;对它们进行排序？键，其中所有更大的值应该在顶部，但其余的对象应该使用＆＃34; unix_time＆＃34;键。

Answer 1

使用Array#sort方法和自定义比较功能。

var data=[{"user":"a", "msg":"Hi ", "msg_count":1, "unix_time":"1474476800000"},
{"user":"b", "msg":"Hi ", "msg_count":1, "unix_time":"1478776800000"},
{"user":"c", "msg":"Hi ", "msg_count":5, "unix_time":"1479276800000"},
{"user":"d", "msg":"Hi ", "msg_count":1, "unix_time":"1478416800000"},
{"user":"e", "msg":"Hi ", "msg_count":3, "unix_time":"1478476800000"}];


data.sort(function(a, b) {
  // return the difference of `msg_count` property to sort based on them
  // if they are equal then sort based on unix_time prop
  return b.msg_count - a.msg_count || 
    b.unix_time - a.unix_time;
})

console.log(data)

使用两个键

1 个答案: