Question

如何设置以编程方式创建的按钮的属性？例如：在我下面的例子中，我想创建一个＆＃34; android：layout_weight =＆＃34; 1＆＃34;＆＃34;和＆＃34; on_click =＆＃34; startsearch＆＃34;＆＃34;属于我的＆＃34; Place＆＃34;按钮。

    List<DB_Verlauf_Contact> placeList = db.getAllDBPlaces();
    LinearLayout layout = (LinearLayout) findViewById(R.id.verlauf_liste);

    for (DB_Verlauf_Contact cn : placeList) {
        String log = "Id: "+cn.getID()+" ,Place ID: " + cn.getPlace_id() + " ,Name: " + cn.getName()+ " ,Longitude: " + cn.getLongitude()+ " ,Latitude: " + cn.getLatitude();
        LinearLayout row = new LinearLayout(this);
        row.setLayoutParams(new ViewGroup.LayoutParams(ViewGroup.LayoutParams.MATCH_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT));

        Button Place = new Button(this);
        Place.setLayoutParams(new ViewGroup.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT));
        Place.setText(cn.getName());
        Place.setId(cn.getID());
        row.addView(Place);

        Button Delete = new Button(this);
        Delete.setLayoutParams(new ViewGroup.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT));
        Delete.setText("Löschen");
        Delete.setId(cn.getID());
        row.addView(Delete);

        layout.addView(row);
        Log.d("Name: ", log);
    }

Answer 1

一起去：

Button place = new Button(this);
LinearLayout.LayoutParams params = (LinearLayout.LayoutParams) place.getLayoutParams();
params.weight = 1.0f;
place.setLayoutParams(params);


place.setOnClickListener(new OnClickListener() {
    @Override
    public void onClick(View v) {
        //handle the click
    }
});

实例名称应以小写字母开头。

如何设置以编程方式创建的按钮的属性？

1 个答案: