Question

我在我的Android应用程序中使用以下代码：

Button selectedButton = null;
        if(mSelectedTimePeriod.equals(ChartImageData.LAST_1_DAY)){
            selectedButton = mButton1;
        }else if(mSelectedTimePeriod.equals(ChartImageData.LAST_5_DAYS)){
            selectedButton = mButton2;
        }else if(mSelectedTimePeriod.equals(ChartImageData.LAST_30_DAYS)){
            selectedButton = mButton3;
        }else if(mSelectedTimePeriod.equals(ChartImageData.LAST_3_MONTHS)){
            selectedButton = mButton4;
        }else if(mSelectedTimePeriod.equals(ChartImageData.LAST_6_MONTHS)){
            selectedButton = mButton5;
        }else if(mSelectedTimePeriod.equals(ChartImageData.LAST_1_YEAR)){
            selectedButton = mButton6;
        }else if(mSelectedTimePeriod.equals(ChartImageData.LAST_5_YEARS)){
            selectedButton = mButton7;
        }
        return selectedButton;

有没有办法让mbutton1像mbutton [i]和LAST_1_DAY = LAST_ [i] _DAY？并把它全部放在一个循环或其他什么所以当选择后续按钮时，数字会相应加载？

Answer 1

您可以创建字符串和按钮的映射。

    Map<String, Button> mapping = new HashMap<String, Button>()
    mapping.put(ChartImageData.LAST_1_DAY, mbutton1);
    mapping.put(ChartImageData.LAST_5_DAYS, mbutton2);
    ....

然后你就可以做到。

     return mapping.get(mSelectedTimePeriod);

如果您将来添加额外的按钮，这也会更容易。您需要做的就是将其添加到地图中。

有没有办法可以将这些语句简化为几行代码？

1 个答案: