使用if语句进行简单登录表单PHP

Question

我试图根据此序列中的会话编写一个简单的登录系统。 虽然在第一个位置登录用户工作但第二个用户没有登录。我无法找到错误的位置。 以下是 login.php 表单的代码。

include './user.php';

session_start();

    if (!empty($_POST['form-username'])) {

    if($_POST['form-username']==$user && $_POST['form-password']==$pass){

        $_SESSION['login'] = $_POST['form-username'];
        $_SESSION['password'] = $_POST['form-password'];
        header("Location: ./dashboard.php");

    }else if($_POST['form-username']==$user2 && $_POST['form-password']==$pass2){

        $_SESSION['login'] = $_POST['form-username'];
        $_SESSION['password'] = $_POST['form-password'];
        header("Location: ./dashboard.php");
    }

    else {

        header("Location: ./index.php?err");
        //exit;
    }

    }
    if(!empty($_SESSION['login'])):
        if($_SESSION['login']==$user AND $_SESSION['password']==$pass || $_SESSION['login']==$user2 AND $_SESSION['password']==$pass2){

            header("Location: ./dashboard.php");

        }
    endif;

以下是 user.php 文件的代码：

<?php

   $user = 'panel1';
   $pass = 'panel123';

   $user2 ='panel2';
   $pass2 = 'panel091';

Answer 1

我认为您应该尝试将上一个if声明更改为：

if (($_SESSION['login'] == $user AND $_SESSION['password'] == $pass) OR ($_SESSION['login'] == $user2 AND $_SESSION['password'] == $pass2)) {
  // ...
}

注意每个条件周围的包裹约束。